1990 United States House of Representatives elections in Virginia
The 1990 United States House of Representatives elections in Virginia were held on November 6, 1990 to determine who will represent the Commonwealth of Virginia in the United States House of Representatives. Virginia had ten seats in the House, apportioned according to the 1980 United States Census. Representatives are elected for two-year terms.
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All 10 Virginia seats to the United States House of Representatives | |||||||||||||||||||||||||||||||||
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| Elections in Virginia | ||||||||||||
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Overview
| United States House of Representatives elections in Virginia, 1990[1] | |||||
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| Party | Votes | Percentage | Seats | +/– | |
| Democratic | 662,800 | 57.49% | 6 | +1 | |
| Republican | 410,941 | 35.64% | 4 | -1 | |
| Independents/Write-ins | 79,133 | 6.86% | 0 | - | |
| Totals | 1,152,874 | 100.00% | 10 | - | |
See also
- United States House elections, 1990
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