1990 United States Senate election in Rhode Island
The 1990 Rhode Island United States Senate election was held on November 6, 1990 to select the U.S. Senator from the state of Rhode Island. Democratic U.S. Senator Claiborne Pell decided to seek re-election and defeated Republican Representative Claudine Schneider in a landslide.[1]
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Candidates
Democrat
- Claiborne Pell, incumbent U.S. Senator
Republican
- Claudine Schneider, U.S. Representative
Results
| Party | Candidate | Votes | % | ± | |
|---|---|---|---|---|---|
| Democratic | Claiborne Pell (Incumbent) | 225,105 | 61.83% | -10.83% | |
| Republican | Claudine Schneider | 138,947 | 38.17% | +10.83% | |
| Majority | 86,158 | 23.67% | -21.65% | ||
| Turnout | 364,062 | ||||
| Democratic hold | Swing | ||||
See also
- United States Senate elections, 1990 and 1991
References
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