1946 United States House of Representatives elections in Virginia
The 1946 United States House of Representatives elections in Virginia were held on November 5, 1946 to determine who will represent the Commonwealth of Virginia in the United States House of Representatives. Virginia had nine seats in the House, apportioned according to the 1940 United States Census. Representatives are elected for two-year terms.
| Elections in Virginia | ||||||||||||
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Overview
| United States House of Representatives elections in Virginia, 1946[1] | |||||
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| Party | Votes | Percentage | Seats | +/– | |
| Democratic | 167,919 | 66.15% | 9 | - | |
| Republican | 81,626 | 32.15% | 0 | - | |
| Prohibition | 2,012 | 0.79% | 0 | - | |
| Socialist | 272 | 0.11% | 0 | - | |
| Independents/Write-ins | 2,035 | 0.80% | 0 | - | |
| Totals | 253,864 | 100.00% | 9 | - | |
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