1948 United States presidential election in Wisconsin

The 1948 United States presidential election in Wisconsin was held on November 2, 1948 as part of the 1948 United States presidential election. State voters chose twelve electors to the Electoral College, who voted for president and vice president.

Main article: 1948 United States presidential election

1948 United States presidential election in Wisconsin

November 2, 1948

Nominee Harry S. Truman Thomas E. Dewey Party Democratic Republican Home state Missouri New York Running mate Alben W. Barkley Earl Warren Electoral vote 12 0 Popular vote 647,310 590,959 Percentage 50.7% 46.3%

County Results Truman   40-50%   50-60%   60-70% Dewey   40-50%   50-60%   60-70%

President before election Harry S. Truman Democratic Elected President Harry S. Truman Democratic

Democratic Party candidate Harry S. Truman won Wisconsin with 51% of the popular vote, winning the state's twelve electoral votes.[1]

Results

1948 United States presidential election in Wisconsin
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Harry S. Truman	647,310	50.70%	12
	Republican	Thomas E. Dewey	590,959	46.28%	0
	Progressive	Henry A. Wallace	25,282	1.98%	0
	Socialist	Norman Thomas	12,547	0.98%	0
Totals			1,276,098	100.0%	12

References

1. "1948 Presidential General Election Results - Wisconsin". Retrieved August 19, 2016.