1928 United States presidential election in Wisconsin

The 1928 United States presidential election in Wisconsin was held on November 6, 1928 as part of the 1928 United States presidential election. State voters chose thirteen electors to the Electoral College, who voted for president and vice president.

Main article: 1928 United States presidential election

1928 United States presidential election in Wisconsin

November 6, 1928

Nominee Herbert Hoover Al Smith Party Republican Democratic Home state California New York Running mate Charles Curtis Joseph T. Robinson Electoral vote 13 0 Popular vote 544,205 450,259 Percentage 53.52% 44.28%

President before election Calvin Coolidge Republican Elected President Herbert Hoover Republican

Republican Party candidate Herbert Hoover won Wisconsin with 54% of the popular vote, winning the state's thirteen electoral votes.[1] As of the 2016 presidential election, this is the last election in which Douglas County voted for the Republican candidate.

Results

1928 United States presidential election in Wisconsin
Party		Candidate	Votes	Percentage	Electoral votes
	Republican	Herbert Hoover	544,205	53.52%	13
	Democratic	Al Smith	450,259	44.28%	0
	Socialist	Norman Thomas	18,213	1.79%	0
Totals			1,012,677	100.0%	13

References

1. "1928 Presidential General Election Results - Wisconsin". Retrieved August 19, 2016.