1890 Kansas gubernatorial election

The 1890 Kansas gubernatorial election was held on November 4, 1890. Incumbent Republican Lyman U. Humphrey defeated People's Party nominee John F. Willits with 39.05% of the vote.

1890 Kansas gubernatorial election

November 4, 1890

Nominee Lyman U. Humphrey John F. Willits Charles L. Robinson Party Republican People's Democratic Popular vote 115,024 106,945 71,357 Percentage 39.05% 36.31% 24.23%

Governor before election Lyman U. Humphrey Republican Elected Governor Lyman U. Humphrey Republican

General election

Candidates

Major party candidates

• Lyman U. Humphrey, Republican
• Charles L. Robinson, Democratic

Other candidates

• John F. Willits, People's
• A. M. Richardson, Prohibition

Results

1890 Kansas gubernatorial election[1]

Party		Candidate	Votes	%	±
	Republican	Lyman U. Humphrey	115,024	39.05%
	People's	John F. Willits	106,945	36.31%
	Democratic	Charles L. Robinson	71,357	24.23%
	Prohibition	A. M. Richardson	1,230	0.42%
Majority			8,079
Turnout
	Republican hold		Swing

References

1. "Guide to U.S. elections - CQ Press, Congressional Quarterly, inc". Books.google.com. Retrieved 2020-07-05.