Sand Creek Township, Jennings County, Indiana
Sand Creek Township is one of eleven townships in Jennings County, Indiana, United States. As of the 2010 census, its population was 872 and it contained 365 housing units.[1]
Sand Creek Township | |
---|---|
Location in Jennings County | |
Coordinates: 39°05′16″N 85°36′25″W | |
Country | United States |
State | Indiana |
County | Jennings |
Government | |
• Type | Indiana township |
Area | |
• Total | 27.95 sq mi (72.4 km2) |
• Land | 27.72 sq mi (71.8 km2) |
• Water | 0.23 sq mi (0.6 km2) 0.82% |
Elevation | 725 ft (221 m) |
Population (2010) | |
• Total | 872 |
• Density | 31.5/sq mi (12.2/km2) |
GNIS feature ID | 0453833 |
Geography
According to the 2010 census, the township has a total area of 27.95 square miles (72.4 km2), of which 27.72 square miles (71.8 km2) (or 99.18%) is land and 0.23 square miles (0.60 km2) (or 0.82%) is water.[1] The streams of Bear Creek, Fish Creek, Ice Creek, Millstone Creek, Poplar Root Creek and Rock Creek run through this township.
Unincorporated towns
Adjacent townships
- Jackson Township, Decatur County (north)
- Sand Creek Township, Decatur County (north)
- Columbia Township (east)
- Campbell Township (southeast)
- Center Township (south)
- Geneva Township (west)
Cemeteries
The township contains three cemeteries: Bear Creek, Day and Fish Creek.
Major highways
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References
- "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on 2020-02-12. Retrieved 2013-05-10.
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