2019 Silicon Valley Classic – Doubles
Latisha Chan and Květa Peschke were the defending champions[1] but Chan chose not to participate.
Doubles | |
---|---|
2019 Silicon Valley Classic | |
Champions | |
Runners-up | |
Final score | 6−4, 6−4 |
Peschke played alongside Nicole Melichar and successfully defended her title, defeating Shuko Aoyama and Ena Shibahara in the final, 6−4, 6−4.
Seeds
Nicole Melichar / Květa Peschke (Champions) Desirae Krawczyk / Alicja Rosolska (Semifinals) Lyudmyla Kichenok / Nadiia Kichenok (Quarterfinals) Mihaela Buzărnescu / Zhang Shuai (First round)
Draw
Key
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- Alt = Alternate
- SE = Special Exempt
- PR = Protected Ranking
- ITF = ITF entry
- JE = Junior Exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
Draw
First Round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | 77 | 6 | |||||||||||||||||||||||||
2 | 4 | 63 | 1 | ||||||||||||||||||||||||
6 | 6 | 1 | 6 | 4 | [10] | ||||||||||||||||||||||
4 | 3 | 6 | [5] | 4 | 6 | [3] | |||||||||||||||||||||
6 | 1 | [10] | 78 | 0 | [10] | ||||||||||||||||||||||
2 | 6 | [8] | 66 | 6 | [8] | ||||||||||||||||||||||
6 | 4 | [10] | 1 | 6 | 6 | ||||||||||||||||||||||
6 | 6 | 4 | 4 | ||||||||||||||||||||||||
2 | 4 | 6 | 6 | ||||||||||||||||||||||||
65 | 2 | 3 | 1 | 4 | |||||||||||||||||||||||
3 | 77 | 6 | 3 | 6 | [10] | ||||||||||||||||||||||
2 | 4 | 2 | 6 | 3 | [5] | ||||||||||||||||||||||
6 | 6 | 6 | 5 | [8] | |||||||||||||||||||||||
2 | 4 | 7 | [10] | ||||||||||||||||||||||||
gollark: Instead of creating the universes, maybe just simulate some with intelligent life?
gollark: Presumably (',') but with some way to feed in a different value for '?
gollark: I would try to help, but infinite things are too confusing.
gollark: Lazy evaluation makes infinite data structures great.
gollark: I found the Prelude definition of iterate:```haskelliterate :: (a -> a) -> a -> [a]iterate f x = x : iterate f (f x)```
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