2019 Hungarian Ladies Open – Doubles
Georgina García Pérez and Fanny Stollár were the defending champions,[1] but chose not to participate together. García Pérez played alongside Renata Voráčová, but lost in the quarterfinals to Anna Blinkova and Anastasia Potapova.
Doubles | |
---|---|
2019 Hungarian Ladies Open | |
Champions | |
Runners-up | |
Final score | 6–4, 4–6, [10–7] |
Stollár played alongside Heather Watson, but lost in the final to Ekaterina Alexandrova and Vera Zvonareva, 4–6, 6–4, [7–10].
Seeds
Kirsten Flipkens / Johanna Larsson (Withdrew) Irina-Camelia Begu / Galina Voskoboeva (Semifinals) Fanny Stollár / Heather Watson (Final) Jessica Moore / Alexandra Panova (First round)
Draw
Key
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- Alt = Alternate
- SE = Special Exempt
- PR = Protected Ranking
- ITF = ITF entry
- JE = Junior Exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
Draw
First Round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | |||||||||||||||||||||||||||
w/o | 63 | 63 | |||||||||||||||||||||||||
7 | 2 | [12] | 77 | 77 | |||||||||||||||||||||||
5 | 6 | [10] | 4 | 6 | [10] | ||||||||||||||||||||||
4 | 6 | 65 | [13] | 6 | 4 | [6] | |||||||||||||||||||||
4 | 77 | [15] | 6 | 3 | [11] | ||||||||||||||||||||||
6 | 4 | [10] | 4 | 6 | [9] | ||||||||||||||||||||||
3 | 6 | [3] | 6 | 4 | [10] | ||||||||||||||||||||||
WC | 4 | 6 | [5] | 3 | 4 | 6 | [7] | ||||||||||||||||||||
6 | 1 | [10] | 6 | 3 | [4] | ||||||||||||||||||||||
64 | 4 | 3 | 1 | 6 | [10] | ||||||||||||||||||||||
3 | 77 | 6 | 3 | 6 | 6 | ||||||||||||||||||||||
2 | 6 | [9] | 2 | 2 | 3 | ||||||||||||||||||||||
6 | 4 | [11] | 4 | 5 | |||||||||||||||||||||||
WC | 3 | 6 | [9] | 2 | 6 | 7 | |||||||||||||||||||||
2 | 6 | 1 | [11] |
gollark: If they know other people on the network you can connect through them.
gollark: People you know somehow?
gollark: The internet itself doesn't really depend on a central authority, also.
gollark: Which do not have to be central.
gollark: You need an initial peer, I suppose, but someone can just tell you one via other means.
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