2019 Japan Women's Open – Doubles
Eri Hozumi and Zhang Shuai were the defending champions,[1] but Zhang chose to compete in Nanchang instead. Hozumi played alongside Makoto Ninomiya, but lost in the quarterfinals to Christina McHale and Valeria Savinykh.
Doubles | |
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2019 Japan Women's Open | |
Champions | ![]() ![]() |
Runners-up | ![]() ![]() |
Final score | 3–6, 6–4, [10–4] |
Misaki Doi and Nao Hibino won the title, defeating McHale and Savinykh in the final, 3–6, 6–4, [10–4].
Seeds
Eri Hozumi / Makoto Ninomiya (Quarterfinals) Kirsten Flipkens / Alison Van Uytvanck (First round) Mihaela Buzărnescu / Katarina Srebotnik (First round) Georgina García Pérez / Sara Sorribes Tormo (First round)
Draw
Key
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- Alt = Alternate
- SE = Special Exempt
- PR = Protected Ranking
- ITF = ITF entry
- JE = Junior Exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
Draw
First Round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | ![]() ![]() | 6 | 6 | ||||||||||||||||||||||||
![]() ![]() | 3 | 4 | 1 | ![]() ![]() | 5 | 2 | |||||||||||||||||||||
![]() ![]() | 6 | 6 | ![]() ![]() | 7 | 6 | ||||||||||||||||||||||
WC | ![]() ![]() | 4 | 3 | ![]() ![]() | 6 | 6 | |||||||||||||||||||||
4 | ![]() ![]() | 4 | 4 | ![]() ![]() | 4 | 1 | |||||||||||||||||||||
![]() ![]() | 6 | 6 | ![]() ![]() | 3 | 2 | ||||||||||||||||||||||
![]() ![]() | 7 | 6 | ![]() ![]() | 6 | 6 | ||||||||||||||||||||||
![]() ![]() | 5 | 2 | ![]() ![]() | 6 | 4 | [4] | |||||||||||||||||||||
![]() ![]() | 6 | 6 | ![]() ![]() | 3 | 6 | [10] | |||||||||||||||||||||
![]() ![]() | 4 | 2 | ![]() ![]() | 5 | 4 | ||||||||||||||||||||||
![]() ![]() | 6 | 6 | ![]() ![]() | 7 | 6 | ||||||||||||||||||||||
3 | ![]() ![]() | 4 | 3 | ![]() ![]() | 3 | 4 | |||||||||||||||||||||
![]() ![]() | 77 | 610 | [10] | ![]() ![]() | 6 | 6 | |||||||||||||||||||||
WC | ![]() ![]() | 65 | 712 | [7] | ![]() ![]() | ||||||||||||||||||||||
![]() ![]() | 3 | 6 | [10] | ![]() ![]() | w/o | ||||||||||||||||||||||
2 | ![]() ![]() | 6 | 4 | [7] |
gollark: You may, however, be able to poke at local vars or something to make this work. Maybe?
gollark: ```inspect.getsource(lambda a: a)Traceback (most recent call last): File "<stdin>", line 1, in <module> File "/usr/lib/python3.6/inspect.py", line 973, in getsource lines, lnum = getsourcelines(object) File "/usr/lib/python3.6/inspect.py", line 955, in getsourcelines lines, lnum = findsource(object) File "/usr/lib/python3.6/inspect.py", line 786, in findsource raise OSError('could not get source code')OSError: could not get source code```
gollark: Hmm, seems you can get the bytecode, checking about non-bytecode.
gollark: There's an AST parsing module.
gollark: <@205053980923920385> You can at least get the source, probably.
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