2018 Pingshan Open – Men's Doubles

Sanchai and Sonchat Ratiwatana were the defending champions but chose not to defend their title.

Men's Doubles
2018 Pingshan Open
Champions Hsieh Cheng-peng
Rameez Junaid
Runners-up Denys Molchanov
Igor Zelenay
Final score7–6(7–3), 6–3
Main article: 2018 Pingshan Open

Hsieh Cheng-peng and Rameez Junaid won the title after defeating Denys Molchanov and Igor Zelenay 7–6(7–3), 6–3 in the final.

Seeds
  1. Sriram Balaji / Christopher Rungkat (Quarterfinals)
  2. Denys Molchanov / Igor Zelenay (Final)
  3. Marin Draganja / Tomislav Draganja (Quarterfinals)
  4. Aliaksandr Bury / Peng Hsien-yin (Semifinals)

Draw

Key
First Round Quarterfinals Semifinals Final
1 S Balaji
C Rungkat 		6 6
Y He
Zh Zhang 		4 4 1 S Balaji
C Rungkat 		7 4 [8]
T Matsui
C-h Yi 		4 5 C-p Hsieh
R Junaid 		5 6 [10]
C-p Hsieh
R Junaid 		6 7 C-p Hsieh
R Junaid 		77 3 [10]
4 A Bury
H-y Peng 		6 6 4 A Bury
H-y Peng 		63 6 [7]
S Caruso
A Vatutin 		1 2 4 A Bury
H-y Peng 		2 6 [10]
M Elgin
A Siljeström 		77 6 M Elgin
A Siljeström 		6 2 [7]
L Sonego
A Vavassori 		63 4 C-p Hsieh
R Junaid 		77 6
G Granollers
Z Li 		3 64 2 D Molchanov
I Zelenay 		63 3
R Te
D Wu 		6 77 R Te
D Wu 		4 6 [10]
H Hurkacz
K Majchrzak 		5 65 3 M Draganja
T Draganja 		6 3 [7]
3 M Draganja
T Draganja 		7 77 R Te
D Wu 		2 6 [5]
U Ignatik
T-S Weissborn 		63 6 [11] 2 D Molchanov
I Zelenay 		6 3 [10]
V Galović
N Milojević 		77 2 [13] V Galović
N Milojević 		2 3
X Gao
Ze Zhang 		4 79 [5] 2 D Molchanov
I Zelenay 		6 6
2 D Molchanov
I Zelenay 		6 67 [10]
gollark: ```javascriptconst renderPlayer = (player) => { let str = "" for (let y = player.y - 5; y <= player.y + 5; y++) { for (let x = player.x - 10; x <= player.x + 10; x++) { let wallCol = getWallColor(x, y) if (x >= WIDTH) { str += wallCol } else if (y >= HEIGHT) { str += wallCol } else if (x < 0) { str += wallCol } else if (y < 0) { str += wallCol } else { let id = getEnemy(x, y) if (id != -1) { str += enemy_icons[enemies[id].id] } else { let id = getPlayer(x, y) if (id != -1) { str += players[id].icon } else { let id = getBonus(x, y) if (id != -1) { str += "?" } else { str += " " } } } } } str += "\n" } return str}```
gollark: YES, SOME OFFENSE.
gollark: As I said, this is not very good code.]
gollark: Every rendered tile.
gollark: I suppose baidicoot thought "hmm, how might I find whether a player is on a tile I'm rendering". Now, you might think "hmm yes, the solution to this is just to maintain a map of coordinates to entities, or something like that". But no! The game ITERATES OVER ALL PLAYERS FOR EVERY SINGLE TILE.

References
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.