2018 Copa Sevilla – Doubles
Pedro Cachín and Íñigo Cervantes were the defending champions but chose not to defend their title.
Doubles | |
---|---|
2018 Copa Sevilla | |
Champions | ![]() ![]() |
Runners-up | ![]() ![]() |
Final score | 6–0, 6–2 |
Gerard Granollers and Pedro Martínez won the title after defeating Daniel Gimeno Traver and Ricardo Ojeda Lara 6–0, 6–2 in the final.
Seeds
Fabrício Neis / David Vega Hernández (First round) Ariel Behar / Enrique López Pérez (Semifinals) Tomislav Brkić / Ante Pavić (First round) Gerard Granollers / Pedro Martínez (Champions)
Draw
Key
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- Alt = Alternate
- SE = Special Exempt
- PR = Protected Ranking
- ITF = ITF entry
- JE = Junior Exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
First Round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | ![]() ![]() | 4 | 4 | ||||||||||||||||||||||||
![]() ![]() | 6 | 6 | ![]() ![]() | 3 | 710 | [10] | |||||||||||||||||||||
![]() ![]() | 77 | 6 | ![]() ![]() | 6 | 68 | [8] | |||||||||||||||||||||
WC | ![]() ![]() | 65 | 2 | ![]() ![]() | 3 | 68 | |||||||||||||||||||||
3 | ![]() ![]() | 6 | 4 | [8] | WC | ![]() ![]() | 6 | 710 | |||||||||||||||||||
WC | ![]() ![]() | 4 | 6 | [10] | WC | ![]() ![]() | 6 | 6 | |||||||||||||||||||
Alt | ![]() ![]() | 7 | 6 | Alt | ![]() ![]() | 3 | 4 | ||||||||||||||||||||
![]() ![]() | 5 | 3 | WC | ![]() ![]() | 0 | 2 | |||||||||||||||||||||
![]() ![]() | 1 | 4 | 4 | ![]() ![]() | 6 | 6 | |||||||||||||||||||||
WC | ![]() ![]() | 6 | 6 | WC | ![]() ![]() | 3 | 4 | ||||||||||||||||||||
![]() ![]() | 4 | 2 | 4 | ![]() ![]() | 6 | 6 | |||||||||||||||||||||
4 | ![]() ![]() | 6 | 6 | 4 | ![]() ![]() | 3 | 77 | [10] | |||||||||||||||||||
![]() ![]() | 3 | 4 | 2 | ![]() ![]() | 6 | 65 | [4] | ||||||||||||||||||||
![]() ![]() | 6 | 6 | ![]() ![]() | 4 | 65 | ||||||||||||||||||||||
![]() ![]() | 2 | 4 | 2 | ![]() ![]() | 6 | 77 | |||||||||||||||||||||
2 | ![]() ![]() | 6 | 6 |
gollark: And maybe whatever #12 does.
gollark: Apart from QOI.
gollark: It's probably the second-fanciest algorithm in the challenge, though.
gollark: Well, yes.
gollark: It uses two steps: BPE (ish) and asymmetric numeral systems (brokenly).
References
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