2016 Shanghai Challenger – Doubles
Wu Di and Yi Chu-huan were the defending champions but chose not to compete together. Wu played alongside Zhang Zhizhen. Yi teamed up with Hsieh Cheng-peng. Wu lost in the quarterfinals to Gao Xin and Li Zhe.
Doubles | |
---|---|
2016 Shanghai Challenger | |
Champions | |
Runners-up | |
Final score | 7–6(8–6), 5–7, [10–0] |
Yi successfully defended his title, defeating Gao and Li 7–6(8–6), 5–7, [10–0] in the final.
Seeds
Sanchai Ratiwatana / Sonchat Ratiwatana (Quarterfinals) Sergey Betov / Denys Molchanov (First round) Gong Maoxin / Zhang Ze (Semifinals) Hsieh Cheng-peng / Yi Chu-huan (Champions)
Draw
Key
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- Alt = Alternate
- SE = Special Exempt
- PR = Protected Ranking
- ITF = ITF entry
- JE = Junior Exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
First Round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | 6 | 6 | |||||||||||||||||||||||||
WC | 2 | 2 | 1 | 67 | 6 | [8] | |||||||||||||||||||||
4 | 7 | [11] | 79 | 2 | [10] | ||||||||||||||||||||||
6 | 5 | [9] | 5 | 65 | |||||||||||||||||||||||
4 | 6 | 77 | 4 | 7 | 77 | ||||||||||||||||||||||
WC | 1 | 63 | 4 | 6 | 4 | [10] | |||||||||||||||||||||
6 | 7 | 3 | 6 | [6] | |||||||||||||||||||||||
3 | 5 | 4 | 78 | 5 | [10] | ||||||||||||||||||||||
2 | 61 | 66 | 7 | [0] | |||||||||||||||||||||||
6 | 77 | 6 | 3 | [6] | |||||||||||||||||||||||
PR | 1 | 4 | 3 | 1 | 6 | [10] | |||||||||||||||||||||
3 | 6 | 6 | 3 | 77 | 4 | [5] | |||||||||||||||||||||
WC | 6 | 6 | 63 | 6 | [10] | ||||||||||||||||||||||
2 | 2 | WC | 3 | 4 | |||||||||||||||||||||||
5 | 6 | [10] | 6 | 6 | |||||||||||||||||||||||
2 | 7 | 3 | [8] |
gollark: So you can kill people without living family? Fun!
gollark: Apparently people like "negative average preference utilitarianism", where you have to produce the least average amount of dissatisfied preferences.
gollark: Do we *really*?
gollark: The "arithmetic mean".
gollark: You could use something known as the "mean".
References
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