2014 İstanbul Cup – Doubles
Eleni Daniilidou and Jasmin Wöhr were the last champions of the event in 2010, but decided not to participate.
Misaki Doi and Elina Svitolina won the title, defeating Oksana Kalashnikova and Paula Kania in the final, 6–4, 6–0.
Doubles | |
---|---|
2014 İstanbul Cup | |
Champions | ![]() ![]() |
Runners-up | ![]() ![]() |
Final score | 6–4, 6–0 |
Seeds
Irina Buryachok / Alla Kudryavtseva (First round) Karolína Plíšková / Kristýna Plíšková (Quarterfinals) Yuliya Beygelzimer / Olga Savchuk (Quarterfinals) Janette Husárová / Klaudia Jans-Ignacik (Semifinals)
Draw
Key
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- Alt = Alternate
- SE = Special Exempt
- PR = Protected Ranking
- ITF = ITF entry
- JE = Junior Exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
Draw
First Round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | ![]() ![]() | 3 | 6 | [9] | |||||||||||||||||||||||
![]() ![]() | 6 | 3 | [11] | ![]() ![]() | 4 | 65 | |||||||||||||||||||||
![]() ![]() | 62 | 2 | ![]() ![]() | 6 | 77 | ||||||||||||||||||||||
![]() ![]() | 77 | 6 | ![]() ![]() | 64 | 6 | [10] | |||||||||||||||||||||
4 | ![]() ![]() | 2 | 6 | [12] | 4 | ![]() ![]() | 77 | 3 | [6] | ||||||||||||||||||
WC | ![]() ![]() | 6 | 1 | [10] | 4 | ![]() ![]() | 6 | 5 | [10] | ||||||||||||||||||
![]() ![]() | 3 | 3 | WC | ![]() ![]() | 2 | 7 | [5] | ||||||||||||||||||||
WC | ![]() ![]() | 6 | 6 | ![]() ![]() | 6 | 6 | |||||||||||||||||||||
![]() ![]() | 77 | 4 | [8] | ![]() ![]() | 4 | 0 | |||||||||||||||||||||
![]() ![]() | 63 | 6 | [10] | ![]() ![]() | 6 | 6 | |||||||||||||||||||||
![]() ![]() | 0 | 2 | 3 | ![]() ![]() | 0 | 2 | |||||||||||||||||||||
3 | ![]() ![]() | 6 | 6 | ![]() ![]() | 64 | 6 | [12] | ||||||||||||||||||||
![]() ![]() | 6 | 7 | ![]() ![]() | 77 | 4 | [10] | |||||||||||||||||||||
![]() ![]() | 3 | 5 | ![]() ![]() | 3 | 6 | [11] | |||||||||||||||||||||
![]() ![]() | 2 | 6 | [5] | 2 | ![]() ![]() | 6 | 4 | [9] | |||||||||||||||||||
2 | ![]() ![]() | 6 | 3 | [10] |
gollark: Then set the x^4/x^3/x^2/x^1 coefficients and constant terms on each side to be equal and work out a/b/c/d.
gollark: Set it equal to `(x-1)(ax^3+bx^2+cx+d)` (the thing you know it's divisible by times the generalized cubic thingy), and expand that out/simplify.
gollark: It would be annoying and inconsistent if it was 0. It's 1.
gollark: It's 1, or the nice neat recursive factorial calculation algorithms would stop working.
gollark: It's not an example, this seems to be true in all cases.
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