2013 Moorilla Hobart International – Doubles

Irina-Camelia Begu and Monica Niculescu were the defending champions but Niculescu decided not to participate.
Begu teamed up alongside Simona Halep, but they lost in the quarterfinals to Tímea Babos and Mandy Minella.
Garbiñe Muguruza and María Teresa Torró Flor won the title, defeating Babos and Minella in the final 6–3, 7–6(7–5).

Doubles
2013 Moorilla Hobart International
Champions Garbiñe Muguruza
María Teresa Torró Flor
Runners-up Tímea Babos
Mandy Minella
Final score6–3, 7–6(7–5)

Seeds

  1. Anabel Medina Garrigues / Yaroslava Shvedova (Quarterfinals, withdrew)
  2. Jarmila Gajdošová / Klára Zakopalová (Quarterfinals, withdrew)
  3. Nina Bratchikova / Janette Husárová (Quarterfinals)
  4. Līga Dekmeijere / Megan Moulton-Levy (First round)

Draw

Key

First Round Quarterfinals Semifinals Final
1 A Medina Garrigues
Y Shvedova
   
  S Jones
R Marino
6 4 [5]   L Arruabarrena Vecino
L Domínguez Lino
w/o    
  L Arruabarrena Vecino
L Domínguez Lino
4 6 [10]   L Arruabarrena Vecino
L Domínguez Lino
2 2  
4 L Dekmeijere
M Moulton-Levy
5 3     T Babos
M Minella
6 6  
  I-C Begu
S Halep
7 6     I-C Begu
S Halep
61 0  
  S Soler Espinosa
C Suárez Navarro
6 67 [8]   T Babos
M Minella
77 6  
  T Babos
M Minella
3 79 [10]   T Babos
M Minella
3 65  
  A Barty
B Bobusic
6 6     G Muguruza
MT Torró Flor
6 77  
  S Bengson
J Moore
1 3     A Barty
B Bobusic
7 7  
WC A Hibberd
J Smith
1 3   3 N Bratchikova
J Husárová
5 5  
3 N Bratchikova
J Husárová
6 6     A Barty
B Bobusic
6 67 [2]
  G Muguruza
MT Torró Flor
6 6     G Muguruza
MT Torró Flor
2 79 [10]
WC V Dobson
K Wlodarczak
1 1     G Muguruza
MT Torró Flor
w/o    
  A Cornet
A Klepač
3 4   2 J Gajdošová
K Zakopalová
   
2 J Gajdošová
K Zakopalová
6 6  
gollark: Oh, bee you autobotrobot.
gollark: ++exec -L sqlite```sqlWITH RECURSIVEinput(sud) AS (VALUES('53..7....6..195....98....6.8...6...34..8.3..17...2...6.6....28....419..5....8..79') ), digits(z, lp) AS (VALUES('1', 1) UNION ALL SELECT CAST(lp+1 AS TEXT), lp+1 FROM digits WHERE lp<9 ), x(s, ind) AS ( SELECT sud, instr(sud, '.') FROM input UNION ALL SELECT substr(s, 1, ind-1) || z || substr(s, ind+1), instr( substr(s, 1, ind-1) || z || substr(s, ind+1), '.' ) FROM x, digits AS z WHERE ind>0 AND NOT EXISTS ( SELECT 1 FROM digits AS lp WHERE z.z = substr(s, ((ind-1)/9)*9 + lp, 1) OR z.z = substr(s, ((ind-1)%9) + (lp-1)*9 + 1, 1) OR z.z = substr(s, (((ind-1)/3) % 3) * 3+ ((ind-1)/27) * 27 + lp+ ((lp-1) / 3) * 6, 1) ) )SELECT s FROM x WHERE ind=0;```UTTERLY you.
gollark: It's not flawed. The freeform input means you can just put two lines on.
gollark: It begins.
gollark: From another thing.

References

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