2013 Challenger of Dallas – Doubles
Chris Eaton and Dominic Inglot were the defending champions but decided not to participate.
Alex Kuznetsov and Mischa Zverev defeated Tennys Sandgren and Rhyne Williams 6–4, 6–7(7–4), [10–5] in the final to capture the title.
Doubles | |
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2013 Challenger of Dallas | |
Champions | ![]() ![]() |
Runners-up | ![]() ![]() |
Final score | 6–4, 6–7(7–4), [10–5] |
Seeds
Rik de Voest / Marcelo Demoliner (Quarterfinals) Stefano Ianni / Denys Molchanov (First Round) Devin Britton / Austin Krajicek (Semifinals) Alex Bogomolov Jr. / Steve Johnson (Quarterfinals, withdrew because of Bogomolov's right shoulder injury)
Draw
Key
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- Alt = Alternate
- SE = Special Exempt
- PR = Protected Ranking
- ITF = ITF entry
- JE = Junior Exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
Draw
First Round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | ![]() ![]() | 7 | 3 | [10] | |||||||||||||||||||||||
![]() ![]() | 5 | 6 | [7] | 1 | ![]() ![]() | 4 | 0 | ||||||||||||||||||||
WC | ![]() ![]() | 1 | 3 | ![]() ![]() | 6 | 6 | |||||||||||||||||||||
![]() ![]() | 6 | 6 | ![]() ![]() | 64 | 6 | [10] | |||||||||||||||||||||
3 | ![]() ![]() | 6 | 6 | 3 | ![]() ![]() | 77 | 4 | [6] | |||||||||||||||||||
![]() ![]() | 1 | 1 | 3 | ![]() ![]() | 6 | 6 | |||||||||||||||||||||
WC | ![]() ![]() | 4 | 3 | ![]() ![]() | 2 | 4 | |||||||||||||||||||||
![]() ![]() | 6 | 6 | ![]() ![]() | 4 | 77 | [5] | |||||||||||||||||||||
Q | ![]() ![]() | 6 | 2 | [4] | ![]() ![]() | 6 | 64 | [10] | |||||||||||||||||||
![]() ![]() | 4 | 6 | [10] | ![]() ![]() | w/o | ||||||||||||||||||||||
![]() ![]() | 3 | 5 | 4 | ![]() ![]() | |||||||||||||||||||||||
4 | ![]() ![]() | 6 | 7 | ![]() ![]() | 6 | 6 | |||||||||||||||||||||
WC | ![]() ![]() | 2 | 1 | Alt | ![]() ![]() | 4 | 3 | ||||||||||||||||||||
![]() ![]() | 6 | 6 | ![]() ![]() | 4 | 2 | ||||||||||||||||||||||
Alt | ![]() ![]() | 3 | 6 | [10] | Alt | ![]() ![]() | 6 | 6 | |||||||||||||||||||
2 | ![]() ![]() | 6 | 3 | [8] |
gollark: Not on arduinos according to a random result I duckduckgoed.
gollark: `int` is 2 bytes, so -32768 to 32767 works.
gollark: It can still handle variables more than 8 bits.
gollark: > the arduino is an 8bit device anything that's more than 255 overflows???
gollark: Also, invite link for your bot (for purposes only)?
References
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