2003 Paris–Roubaix
The 2003 Paris–Roubaix was the 101st running of the Paris–Roubaix single-day cycling race, often known as the Hell of the North. It was held on 13 April 2003 over a distance of 261 kilometres (162.2 miles). These are the results for the 2003 edition of the Paris–Roubaix cycling classic, in which Peter Van Petegem entered history by doing the double with his Tour of Flanders win, 26 years after Roger De Vlaeminck. This edition was run under clear skies and relatively good weather.
Race details | |||||||||||||
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Dates | April 13 | ||||||||||||
Stages | 1 | ||||||||||||
Distance | 261 km (162.2 mi) | ||||||||||||
Winning time | 6h 11' 35" | ||||||||||||
Results | |||||||||||||
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Results
13-04-2003: Compiègne–Roubaix, 259 km.
Cyclist | Team | Time | |
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1 | Lotto–Domo | 6h 11'35" | |
2 | Saeco Macchine per Caffè | s.t. | |
3 | U.S. Postal Service | s.t. | |
4 | Rabobank | + 15" | |
5 | Team CSC | + 36" | |
6 | Vini Caldirola–So.di | + 36" | |
7 | Quick-Step–Davitamon | + 36" | |
8 | Team Telekom | + 36" | |
9 | Team Telekom | + 36" | |
10 | Fassa Bortolo | + 1' 08" |
gollark: This is a straight line, so the result should be the same whichever pair of points you pick.
gollark: =tex \frac{22-19}{7-6}
gollark: So, for example:
gollark: Then divide the difference between the y values by the difference in the x values.
gollark: Subtract one of the x values from another x value, and then the y value matched with the first one from the y value matched with the second one.
References
- Jeff Jones (2003-04-13). "Who will reign in the Queen of the Classics?". Cyclingnews.com. Bath, UK: Future plc. Retrieved 2012-09-26.
External links
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