1925 Paris–Roubaix
The 1925 Paris–Roubaix was the 26th edition of the Paris–Roubaix, a classic one-day cycle race in France. The single day event was held on 12 April 1925 and stretched 260 km (162 mi) from Paris to its end in a velodrome in Roubaix.[1] The winner was Félix Sellier from Belgium.[2]
Race details | ||||||||||
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Dates | 12 April | |||||||||
Stages | 1 | |||||||||
Distance | 260 km (161.6 mi) | |||||||||
Winning time | 9h 16' 32" | |||||||||
Results | ||||||||||
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Results
Rank | Cyclist | Time |
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1 | ![]() |
9h 16' 32″ |
2 | ![]() |
+0' 00″ |
3 | ![]() |
+0' 00″ |
4 | ![]() |
+0' 00″ |
5 | ![]() |
+0' 00″ |
6 | ![]() |
+0' 00″ |
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References
- "26th Paris – Roubaix, 1925". bikeraceinfo. Retrieved 2 April 2015.
- "1925 » 26th Paris – Roubaix". ProCyclingStats. Retrieved 2 April 2015.
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