1905 Paris–Roubaix
The 1905 Paris–Roubaix was the tenth edition of the Paris–Roubaix, a classic one-day cycle race in France. The single day event was held on 23 April 1905 and stretched 268 km (167 mi) from Paris to its end in a velodrome in Roubaix.[1] The winner was Louis Trousselier from France.[2]
Race details | ||||||||||
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Dates | 23 April | |||||||||
Stages | 1 | |||||||||
Distance | 268 km (166.5 mi) | |||||||||
Winning time | 8h 4' 15" | |||||||||
Results | ||||||||||
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Results
Rank | Cyclist | Time |
---|---|---|
1 | 8h 4' 15″ | |
2 | +7' 00″ | |
3 | +16' 00″ | |
4 | +23' 00″ | |
5 | +48' 00″ | |
6 | +57' 00″ | |
7 | +1hr 6' 00″ | |
8 | +1hr 12' 00″ | |
9 | +1hr 20' 00″ | |
10 | +1hr 20' 01″ | |
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References
- "10th Paris – Roubaix, 1905". bikeraceinfo. Retrieved 27 February 2015.
- "1905 » 10th Paris – Roubaix". ProCyclingStats. Retrieved 27 February 2015.
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