1990 Saxony state election
The 1990 Saxony state election was held on 14 October 1990 to elect the members of the first Landtag of Saxony. It was the first election held in Saxony since the reunification of Germany, which took place on 3 October. The Christian Democratic Union (CDU) led by Kurt Biedenkopf dominated the election with 53.8% of the vote, followed by the Social Democratic Party (SPD) with 19.1%. Biedenkopf subsequently became Saxony's first post-reunification Minister-President.
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All 160 seats in the Landtag of Saxony 81 seats needed for a majority | ||||||||||||||||||||||||||||||||||||||||||||
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| Turnout | 2,632,455 (72.8%) | |||||||||||||||||||||||||||||||||||||||||||
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Parties
The table below lists parties which won seats in the election.
| Name | Ideology | Leader(s) | ||
|---|---|---|---|---|
| CDU | Christian Democratic Union of Germany Christlich Demokratische Union Deutschlands |
Christian democracy | Kurt Biedenkopf | |
| SPD | Social Democratic Party of Germany Sozialdemokratische Partei Deutschlands |
Social democracy | Anke Fuchs | |
| PDS | Party of Democratic Socialism Partei des Demokratischen Sozialismus |
Democratic socialism | ||
| Forum | New Forum Neues Forum |
Green politics | ||
| FDP | Free Democratic Party Freie Demokratische Partei |
Classical liberalism | ||
Election result
Summary of the 14 October 1990 election results for the Landtag of Saxony
| Party | Votes | % | Seats | Seats % | |||
|---|---|---|---|---|---|---|---|
| Christian Democratic Union (CDU) | 1,417,332 | 53.8 | 92 | 57.5 | |||
| Social Democratic Party (SPD) | 502,755 | 19.1 | 32 | 20.0 | |||
| Party of Democratic Socialism (PDS) | 269,420 | 10.2 | 17 | 10.6 | |||
| New Forum (FORUM) | 147,543 | 5.6 | 10 | 6.3 | |||
| Free Democratic Party (FDP) | 138,376 | 5.3 | 9 | 5.6 | |||
| German Social Union (DSU) | 93,347 | 3.5 | 0 | 0 | |||
| Others | 63,682 | 2.4 | 0 | 0 | |||
| Total | 2,632,455 | 100.0 | 160 | ||||
| Voter turnout | 72.8 | ||||||
Source
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| Elections | |
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| Referendums |
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gollark: Which I think gives you 2/15.
gollark: It would be quite annoying on larger things, but if you had, say, a 3-sided die, a 4-sided one, and a 5-sided one, and wanted to have 2 of them show a 1, then the possibilities are just 1, 1, anything and anything, 1, 1 (order is 3-sided, 4-sided, 5-sided).So you can work out the probability of each case (1/3 * 1*4 * 1 and 1 * 1/4 * 1/5) and add them.
gollark: Enumerate all the different possibilities where you have X dice showing 3, work out the probability of each, then add them?
gollark: Just multiply the probabilities for getting side X on each die together?
gollark: You also are probably not running Haskell with its giant runtime on a microcontroller doing those things.
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