1974–75 IIHF European Cup
The 1974–75 European Cup was the tenth edition of the European Cup, IIHF's premier European club ice hockey tournament. The season started on September 1, 1974, and finished on February 19, 1977.
The tournament was won by Krylya Sovetov Moscow, who beat Dukla Jihlava in the final
First round
The first round was played September 1 – December 14, 1974.
Team #1 | Score | Team #2 |
---|---|---|
SG Cortina ![]() |
2:5, 3:4 | ![]() |
SC Saint-Gervais ![]() |
0:7, 2:6 | ![]() |
HK Olimpija Ljubljana ![]() |
6:2, 4:1 | ![]() |
SG Dynamo Weißwasser ![]() |
14:2, 3:2 | ![]() |
Berliner SC ![]() |
7:5, 6:3 | ![]() |
HIFK ![]() |
8:7, 6:7 (3:1 PS) | ![]() |
Second round
The second round was played December 22, 1974 – February 6, 1975.
Team #1 | Score | Team #2 |
---|---|---|
EC KAC ![]() |
8:6, 5:5 | ![]() |
HK Olimpija Ljubljana ![]() |
4:6, 2:8 | ![]() |
Berliner SC ![]() |
3:4, 5:3 | ![]() |
HIFK ![]() |
w/o | ![]() |
Third round
The third round was played in February 1975.
Team #1 | Score | Team #2 |
---|---|---|
EC KAC ![]() |
1:8, 3:7 | ![]() |
Berliner SC ![]() |
1:3, 2:4 | ![]() |
Semifinals
The semifinals were played September 1, 1975 – March 19, 1976.
Team #1 | Score | Team #2 |
---|---|---|
Krylya Sovetov Moscow ![]() |
4:1, 4:3 | ![]() |
HIFK ![]() |
2:7, 4:10 | ![]() |
Finals
The finals were played February 17–19, 1977.
Team #1 | Score | Team #2 |
---|---|---|
Dukla Jihlava ![]() |
3:2, 0:7 | ![]() |
gollark: Divide the difference in Y by the difference in X, yes.
gollark: Take two of the points, subtract one's Y coordinate from the other one's Y coordinate, and do the same for the X coordinates, and divide the difference in Y coords by the difference in X coords.
gollark: <@379441093558927391> I'm assuming that what you want to do is find the equation of the straight line going through those points. So to do that you need the gradient.
gollark: <@379441093558927391>
gollark: Once you have the gradient you just need to work out the y intercept, so put that into the straight line equation (y = mx + c), substitute in the x and y from one of the points, solve for c (y intercept), and you're done.
References
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