1916 United States presidential election in North Dakota

The 1916 United States presidential election in North Dakota took place on November 7, 1916. All contemporary forty-eight states were part of the 1916 United States presidential election. Voters chose five electors to the Electoral College, who voted for president and vice president.

Main article: 1916 United States presidential election

1916 United States presidential election in North Dakota

November 7, 1916

Nominee Woodrow Wilson Charles Evans Hughes Party Democratic Republican Home state New Jersey New York Running mate Thomas R. Marshall Charles W. Fairbanks Electoral vote 5 0 Popular vote 55,206 53,471 Percentage 47.84% 46.34%

President before election Woodrow Wilson Democratic Elected President Woodrow Wilson Democratic

North Dakota was won narrowly by incumbent President Woodrow Wilson (D–New Jersey), running with incumbent Vice President Thomas R. Marshall, with 47.84% of the popular vote, against Associate Justice of the U.S. Supreme Court Charles Evans Hughes (R–New York), running with former Vice President Charles W. Fairbanks, with 46.34% of the popular vote. Apart from the state’s first presidential election in 1892, this is the closest presidential result on record in North Dakota,[1] although the state was only the sixth-closest of the 1916 election.

Wilson had previously won North Dakota four years earlier.

Results

Presidential Candidate	Running Mate	Party	Electoral Vote (EV)	Popular Vote (PV)
Woodrow Wilson	Thomas R. Marshall	Democratic	5[2]	55,206	47.84%
Charles Evans Hughes	Charles W. Fairbanks	Republican	0	53,471	46.34%
Allan L. Benson	George R. Kirkpatrick	Socialist	0	5,716	4.95%
Frank Hanly	Ira Landrith	Prohibition	0	997	0.86%

References

1. "Presidential General Election Results Comparison – North Dakota". Dave Leip’s U.S. Election Atlas.
2. "1916 Presidential General Election Results – North Dakota". Dave Leip’s U.S. Election Atlas. Retrieved 26 December 2019.