I have a file named poll001.html, and need to create 100 copies that are named incrementally (i.e poll002.html, poll003.html...etc). I know this is stupid, but it is what boss-man wants. any suggestions to this with either a script, command-line, or python? Again, sorry this is a ridiculous request.
5 Answers
Some batch-fu. Replace "source-file.html" with your source filename. This'll do your leading zeros, too. Save this as a .BAT or .CMD and let 'er rip.
@echo off
for /L %%i IN (1,1,100) do call :docopy %%i
goto :EOF
:docopy
set FN=00%1
set FN=%FN:~-3%
copy source-file.html poll%FN%.html
Edit:
To solve a less general case in the sprit of sysadmin1138's answer:
@echo off
for /L %%i IN (1,1,9) do copy source-file.html poll00%%i.html
for /L %%i IN (10,1,99) do copy source-file.html poll0%%i.html
copy source-file.html poll100.html
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This answer inspired me to learn more about batch scripting, even though it's eight years old by now, thanks for that! But I'm confused. Isn't the idea to jump to `:end` only after the last iteration of the loop? I wrote a similar script where I replaced the `copy` statement with `ECHO %FN"` and added a new line (`ECHO.`) on the last line after `:end`. When I run this it's clear that `:end` is called once for *every* iteration. What syntax should I used to call `:end` only once at the end of the script? – Egalth Oct 25 '18 at 20:06
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Follow-up: I guess `goto :eof` should be added after the `copy` statement. (Ref: https://stackoverflow.com/a/6728702/5457466) – Egalth Oct 25 '18 at 20:14
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The "goto :EOF" will be called once after the for loop completes. I removed the ":end". ":EOF" is a label that implicitly means End Of File and does not need to actually be present as a label in the file. – Evan Anderson Oct 26 '18 at 12:25
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Thanks for clarifying. I found that adding `goto :eof` immediately after the `copy` statement returns execution to the for loop, and does not actually jump to the end of the file (compare the SO reference in my previous comment). However, putting a `goto :eof` after the loop, as in your edit, does indeed jump to the end of the file. So it seems to me that `goto :eof` behaves differently inside a subroutine compared to when it's called as a single statement. – Egalth Oct 26 '18 at 16:15
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1Think of the CALL as starting a new child CMD processor which begins processing at the label that's being CALLed (with "%1", "%2", etc being the argument that the label was CALLed with). When the child command processor reaches the end of the file (either by "goto :EOF" or by literally hitting the end of file) the child terminates and control returns back to the parent, which in this case, is the FOR loop. – Evan Anderson Oct 26 '18 at 19:17
The following powershell one-liner should do the trick:
2..100 | %{cp poll001.html ("poll{0:D3}.html" -f $_)}
A batch-file should do it. From the top of my head:
for /L %%N in (1,1,100) do echo <html></html> > poll%%N.html
Getting leading zeros in will be a bit trickier, but this should get there. If you need those zeros,
for /L %%N in (1,1,9) do echo <html></html> > poll00%%N.html
for /L %%N in (10,1,99) do echo <html></html> > poll0%%N.html
echo <html></html> > poll100.html
The double percent in front of the N is needed if this is used inside of a batch-file. If you're running this directly from a cmd prompt use a single percent (%N).
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Cute hack re: the leading zeros. I solved for a more general case... >smile< The greater-than and less-than symbols in your "echo" statements are going to cause problems, though I realize you're probably just providing the "html" content there as an example. A literal user might not follow why the script doesn't work as expected. – Evan Anderson Jul 29 '10 at 16:08
Here is very fast (lessTested) version of C# code,
You mentioned a python, this is not that unfortunately You can try convert to python.
Or if someone can explain how this can be run in powershell.
using System;
using System.IO;
namespace TestnaKonzola
{
class Program
{
static void Main(string[] args)
{
Console.WriteLine("Enter The First file name:");
string firstFile = Path.Combine(Environment.CurrentDirectory, Console.ReadLine());
Console.WriteLine("Enter the number of copyes:");
int noOfCopy = int.Parse(Console.ReadLine());
string newFile = string.Empty;
for (int i = 0; i < noOfCopy; i++)
{
newFile = NextAvailableFilename(firstFile);
Console.WriteLine(newFile);
File.Copy(firstFile, newFile);
}
Console.ReadLine();
}
public static string NextAvailableFilename(string path)
{
// Short-cut if already available
if (!File.Exists(path))
return path;
// If path has extension then insert the number pattern just before the extension and return next filename
if (Path.HasExtension(path))
return GetNextFilename(path.Insert(path.LastIndexOf(Path.GetExtension(path)), numberPattern));
// Otherwise just append the pattern to the path and return next filename
return GetNextFilename(path + numberPattern);
}
private static string numberPattern = "{000}";
private static string GetNextFilename(string pattern)
{
string tmp = string.Format(pattern, 1);
if (tmp == pattern)
throw new ArgumentException("The pattern must include an index place-holder", "pattern");
if (!File.Exists(tmp))
return tmp; // short-circuit if no matches
int min = 1, max = 2; // min is inclusive, max is exclusive/untested
while (File.Exists(string.Format(pattern, max)))
{
min = max;
max *= 2;
}
while (max != min + 1)
{
int pivot = (max + min) / 2;
if (File.Exists(string.Format(pattern, pivot)))
min = pivot;
else
max = pivot;
}
return string.Format(pattern, max);
}
}
}
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