1967 Mauritian general election

General elections were held in Mauritius on 7 August 1967. The result was a victory for the Independence Party, an alliance of the Labour Party, Independent Forward Block and Muslim Committee of Action, won 43 of the 70 seats,[1] allowing Labour leader and incumbent Prime Minister Seewoosagur Ramgoolam to form a government.

Mauritius
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The voting system created twenty constituencies on Mauritius, which each elected three members. Two seats were elected by residents of Rodrigues, and eight seats were filled by a system known as "best losers" whereby the electoral commission would appoint eight unsuccessful candidates to ensure that ethnic minorities were fairly represented.[2] Voter turnout was 88.9%.[3]

Results
Party Votes % Seats +/-
Constituency Best-loser Total
Independence Party[a]444,73754.6639443+13
Mauritian Social Democrat Party354,19343.5323427+19
All Mauritius Hindu Congress7,0560.870000
National Socialist Workers Party1,2380.150000
Mauritius Liberation Front8430.100000
Mauritius Workers Party5010.060000
Mauritius Young Communist League4520.060000
Rodrigues Party2320.030000
Total813,67710062870+30
Source: Electoral Commission, Nohlen et al.

a The Independence Party bloc consisted of the Labour Party (PTr) 26 seats, the Independent Forward Bloc (IFB) 12 seats and the Comité d'Action Musulman (CAM) 5 seats.

References
  1. Nohlen, D, Krennerich, M & Thibaut, B (1999) Elections in Africa: A data handbook, p618 ISBN 0-19-829645-2
  2. Mauritius: Background to the 1967 Legislative Assembly election EISA
  3. Mauritius: 1967 Legislative Assembly election results overview EISA
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