1897 Iowa gubernatorial election

The 1897 Iowa gubernatorial election was held on November 2, 1897. Republican nominee L. M. Shaw defeated Democratic nominee Frederick Edward White with 51.27% of the vote.

1897 Iowa gubernatorial election
November 2, 1897
 
Nominee L. M. Shaw Frederick Edward White
Party Republican Democratic
Popular vote 224,729 194,853
Percentage 51.27% 44.46%
Governor before election

Francis M. Drake
Republican

 Elected Governor

L. M. Shaw
Republican

Elections in Iowa

General election

Candidates

Major party candidates

  • L. M. Shaw, Republican
  • Frederick Edward White, Democratic

Other candidates

  • S. P. Leland, Prohibition
  • Charles Lloyd, People's
  • John Cliggett, National Democratic
  • M. J. Kremer, Socialist Labor

Results
1897 Iowa gubernatorial election[1]
Party Candidate Votes % ±
Republican L. M. Shaw 224,729 51.27%
Democratic Frederick Edward White 194,853 44.46%
Prohibition S. P. Leland 8,243 1.88%
People's Charles Lloyd 5,295 1.21%
Independent John Cliggett 4,296 0.98%
Socialist Labor M. J. Kremer 876 0.20%
Majority 29,876
Turnout
Republican hold Swing

References
  1. "Guide to U.S. Elections". Books.google.com. Retrieved August 8, 2020.
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