1891 Iowa gubernatorial election

The 1891 Iowa gubernatorial election was held on November 3, 1891. Incumbent Democrat Horace Boies defeated Republican nominee Herman C. Wheeler with 49.40% of the vote.

1891 Iowa gubernatorial election
November 3, 1891
 
Nominee Horace Boies Herman C. Wheeler
Party Democratic Republican
Popular vote 207,594 199,381
Percentage 49.40% 47.45%
Governor before election

Horace Boies
Democratic

 Elected Governor

Horace Boies
Democratic

Elections in Iowa

General election

Candidates

Major party candidates

  • Horace Boies, Democratic
  • Herman C. Wheeler, Republican

Other candidates

  • A. J. Westfall, People's
  • Isaac T. Gibson, Prohibition

Results
1891 Iowa gubernatorial election[1]
Party Candidate Votes % ±
Democratic Horace Boies 207,594 49.40%
Republican Herman C. Wheeler 199,381 47.45%
People's A. J. Westfall 12,303 2.93%
Prohibition Isaac T. Gibson 915 0.22%
Majority 8,213
Turnout
Democratic hold Swing

References
  1. "Guide to U.S. Elections". Books.google.com. Retrieved August 9, 2020.
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