Van Buren Township, Shelby County, Indiana
Van Buren Township is one of fourteen townships in Shelby County, Indiana. As of the 2010 census, its population was 1,480 and it contained 622 housing units.[3]
Van Buren Township | |
---|---|
Coordinates: 39°39′43″N 85°47′31″W | |
Country | United States |
State | Indiana |
County | Shelby |
Government | |
• Type | Indiana township |
Area | |
• Total | 27.91 sq mi (72.3 km2) |
• Land | 27.9 sq mi (72 km2) |
• Water | 0.01 sq mi (0.03 km2) |
Elevation | 837 ft (255 m) |
Population (2010) | |
• Total | 1,480 |
• Density | 53/sq mi (20/km2) |
FIPS code | 18-78578[2] |
GNIS feature ID | 453952 |
The township was named for Martin Van Buren, the eighth President of the United States.[4]
Geography
According to the 2010 census, the township has a total area of 27.91 square miles (72.3 km2), of which 27.9 square miles (72 km2) (or 99.96%) is land and 0.01 square miles (0.026 km2) (or 0.04%) is water.[3]
Unincorporated towns
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References
- "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.
- "U.S. Census website". United States Census Bureau. Retrieved 2008-01-31.
- "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on 2020-02-12. Retrieved 2013-05-10.
- Shelby County, Indiana History & Families. Turner Publishing Company. 1992. p. 172. ISBN 978-1-56311-078-8.
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