Sherman Township, Hardin County, Iowa

Sherman Township is a township located in Hardin County, Iowa. As of the 2010 Census, its population was 738.[4][1]

Sherman Township
Coordinates: 42°20′23″N 093°24′17″W
Country United States
State Iowa
CountyHardin
Area
  Total35.98 sq mi (93.19 km2)
  Land35.98 sq mi (93.19 km2)
  Water(0%) 0 sq mi ((0%) 0 km2)
Elevation1,142 ft (348 m)
Population
 (2000)
  Total461
  Density13.2/sq mi (5.1/km2)
FIPS code468 697[2][3]
GNIS feature ID0468696

History

Sherman Township was founded in 1870.[5] It is named for William Tecumseh Sherman.[6]

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References

  1. "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.
  2. "U.S. Census website". United States Census Bureau. Retrieved 2008-01-31.
  3. U.S. Geological Survey Geographic Names Information System: Sherman Township, Hardin County, Iowa
  4. "Find a County". National Association of Counties. Retrieved 2011-06-07.
  5. Moir, William J. (1911). Past and Present of Hardin County, Iowa. Unigraphic. pp. 319.
  6. History of Hardin County, Iowa. Union Publishing Company. 1883. pp. 904.
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