Saint-Barthélemy-de-Vals
Saint-Barthélemy-de-Vals is a commune in the Drôme department in southeastern France.
Saint-Barthélemy-de-Vals | |
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 The town hall of Saint-Barthélemy-de-Vals | |
Location of Saint-Barthélemy-de-Vals 
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  Saint-Barthélemy-de-Vals  Saint-Barthélemy-de-Vals | |
| Coordinates: 45°10′12″N 4°52′21″E | |
| Country | France |
| Region | Auvergne-Rhône-Alpes |
| Department | Drôme |
| Arrondissement | Valence |
| Canton | Saint-Vallier |
| Intercommunality | Les Deux Rives de la Région de Saint-Vallier |
| Government | |
| • Mayor (2008–2014) | Pierre Montagne |
| Area 1 | 20.27 km2 (7.83 sq mi) |
| Population (2017-01-01)[1] | 1,869 |
| • Density | 92/km2 (240/sq mi) |
| Time zone | UTC+01:00 (CET) |
| • Summer (DST) | UTC+02:00 (CEST) |
| INSEE/Postal code | 26295 /26240 |
| Elevation | 138–355 m (453–1,165 ft) (avg. 172 m or 564 ft) |
| 1 French Land Register data, which excludes lakes, ponds, glaciers > 1 km2 (0.386 sq mi or 247 acres) and river estuaries. | |
Geography
The Galaure forms most of the commune's northern border.
Population
| Year | Pop. | ±% |
|---|---|---|
| 1911 | 1,313 | — |
| 1962 | 1,132 | −13.8% |
| 1968 | 1,153 | +1.9% |
| 1975 | 1,164 | +1.0% |
| 1982 | 1,365 | +17.3% |
| 1990 | 1,637 | +19.9% |
| 1999 | 1,625 | −0.7% |
| 2008 | 1,838 | +13.1% |
gollark: Good luck.
gollark: Fine.```python# from here: https://github.com/Rapptz/RoboDanny/blob/18b92ae2f53927aedebc25fb5eca02c8f6d7a874/cogs/utils/time.pyshort_timedelta_regex = re.compile("""(?:(?P<years>[0-9]{1,8})(?:years?|y))? # e.g. 2y(?:(?P<months>[0-9]{1,8})(?:months?|mo))? # e.g. 2months(?:(?P<weeks>[0-9]{1,8})(?:weeks?|w))? # e.g. 10w(?:(?P<days>[0-9]{1,8})(?:days?|d))? # e.g. 14d(?:(?P<hours>[0-9]{1,8})(?:hours?|h))? # e.g. 12h(?:(?P<minutes>[0-9]{1,8})(?:minutes?|m))? # e.g. 10m(?:(?P<seconds>[0-9]{1,8})(?:seconds?|s))? # e.g. 15s """, re.VERBOSE)def parse_short_timedelta(text): match = short_timedelta_regex.fullmatch(text) if match is None or not match.group(0): raise ValueError("parse failed") data = { k: int(v) for k, v in match.groupdict(default=0).items() } return datetime.datetime.utcnow() + relativedelta(**data)cal = parsedatetime.Calendar()def parse_humantime(text): time_struct, parse_status = cal.parse(text) if parse_status == 1: return datetime.datetime(*time_struct[:6]) else: raise ValueError("parse failed")def parse_time(text): try: return datetime.datetime.strptime(text, "%d/%m/%Y") except: pass try: return parse_short_timedelta(text) except: pass try: return parse_humantime(text) except: pass raise ValueError("could not parse time")```
gollark: ... no.
gollark: The time parsing logic is kind of inconsistent.
gollark: ++remind 9h32m no you aren't.
See also
References
- "Populations légales 2017". INSEE. Retrieved 6 January 2020.
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