Lacombe, Aude
Lacombe is a commune in the Aude department in southern France.
Lacombe | |
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![]() Coat of arms | |
Location of Lacombe ![]() | |
![]() ![]() Lacombe ![]() ![]() Lacombe | |
Coordinates: 43°23′54″N 2°14′04″E | |
Country | France |
Region | Occitanie |
Department | Aude |
Arrondissement | Carcassonne |
Canton | La Malepère à la Montagne Noire |
Intercommunality | Cabardès Montagne Noire |
Government | |
• Mayor (2008–2014) | Jacqueline Recio |
Area 1 | 14.99 km2 (5.79 sq mi) |
Population (2017-01-01)[1] | 172 |
• Density | 11/km2 (30/sq mi) |
Time zone | UTC+01:00 (CET) |
• Summer (DST) | UTC+02:00 (CEST) |
INSEE/Postal code | 11182 /11310 |
Elevation | 605–886 m (1,985–2,907 ft) (avg. 750 m or 2,460 ft) |
1 French Land Register data, which excludes lakes, ponds, glaciers > 1 km2 (0.386 sq mi or 247 acres) and river estuaries. |
Population
Year | Pop. | ±% |
---|---|---|
1962 | 131 | — |
1968 | 153 | +16.8% |
1975 | 163 | +6.5% |
1982 | 150 | −8.0% |
1990 | 139 | −7.3% |
1999 | 114 | −18.0% |
2008 | 166 | +45.6% |
gollark: Ah...
gollark: It should be okay with regexes or something non-turing-complete.
gollark: Hold on, I can probably make a much nicer one.
gollark: It's kind of bad.
gollark: ```python#!/bin/env python3chars = [chr(n) for n in range(126)]firstchar = chars[0]lastchar = chars[len(chars) - 1]def increment_char(character): return chr(ord(character) + 1)def old_increment_string(string_to_increment): reversed_string = list(reversed(string_to_increment)) # Reverse the string for easier work. for rindex, char in enumerate(reversed_string): if char == lastchar: # If we can't increment this char further, try the next ones. reversed_string[rindex] = firstchar # Set the current char back to the first one. reversed_string[rindex + 1] = increment_char(reversed_string[rindex + 1]) # Increment the next one along. else: # We only want to increment ONE char, unless we need to "carry". reversed_string[rindex] = increment_char(reversed_string[rindex]) break return ''.join(list(reversed(reversed_string)))def increment_string(to_increment): reversed_string = list(to_increment) # Reverse the string for easier work. for rindex, char in enumerate(reversed_string): if char == lastchar: # If we can't increment this char further, try the next ones. reversed_string[rindex] = firstchar # Set the current char back to the first one. reversed_string[rindex + 1] = increment_char(reversed_string[rindex + 1]) # Increment the next one along. else: # We only want to increment ONE char, unless we need to "carry". reversed_string[rindex] = increment_char(reversed_string[rindex]) break return ''.join(list(reversed_string))def string_generator(): length = 0 while 1: length += 1 string = chars[0] * length while True: try: string = increment_string(string) except IndexError: # Incrementing has gone out of the char array, move onto next length break yield string```
See also
References
- "Populations légales 2017". INSEE. Retrieved 6 January 2020.
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