Lacombe, Aude

Lacombe is a commune in the Aude department in southern France.

Lacombe
Coat of arms
Location of Lacombe
Lacombe
Lacombe
Coordinates: 43°23′54″N 2°14′04″E
CountryFrance
RegionOccitanie
DepartmentAude
ArrondissementCarcassonne
CantonLa Malepère à la Montagne Noire
IntercommunalityCabardès Montagne Noire
Government
  Mayor (20082014) Jacqueline Recio
Area
1
14.99 km2 (5.79 sq mi)
Population
 (2017-01-01)[1]
172
  Density11/km2 (30/sq mi)
Time zoneUTC+01:00 (CET)
  Summer (DST)UTC+02:00 (CEST)
INSEE/Postal code
11182 /11310
Elevation605–886 m (1,985–2,907 ft)
(avg. 750 m or 2,460 ft)
1 French Land Register data, which excludes lakes, ponds, glaciers > 1 km2 (0.386 sq mi or 247 acres) and river estuaries.

Population

Historical population
YearPop.±%
1962131    
1968153+16.8%
1975163+6.5%
1982150−8.0%
1990139−7.3%
1999114−18.0%
2008166+45.6%
gollark: Ah...
gollark: It should be okay with regexes or something non-turing-complete.
gollark: Hold on, I can probably make a much nicer one.
gollark: It's kind of bad.
gollark: ```python#!/bin/env python3chars = [chr(n) for n in range(126)]firstchar = chars[0]lastchar = chars[len(chars) - 1]def increment_char(character): return chr(ord(character) + 1)def old_increment_string(string_to_increment): reversed_string = list(reversed(string_to_increment)) # Reverse the string for easier work. for rindex, char in enumerate(reversed_string): if char == lastchar: # If we can't increment this char further, try the next ones. reversed_string[rindex] = firstchar # Set the current char back to the first one. reversed_string[rindex + 1] = increment_char(reversed_string[rindex + 1]) # Increment the next one along. else: # We only want to increment ONE char, unless we need to "carry". reversed_string[rindex] = increment_char(reversed_string[rindex]) break return ''.join(list(reversed(reversed_string)))def increment_string(to_increment): reversed_string = list(to_increment) # Reverse the string for easier work. for rindex, char in enumerate(reversed_string): if char == lastchar: # If we can't increment this char further, try the next ones. reversed_string[rindex] = firstchar # Set the current char back to the first one. reversed_string[rindex + 1] = increment_char(reversed_string[rindex + 1]) # Increment the next one along. else: # We only want to increment ONE char, unless we need to "carry". reversed_string[rindex] = increment_char(reversed_string[rindex]) break return ''.join(list(reversed_string))def string_generator(): length = 0 while 1: length += 1 string = chars[0] * length while True: try: string = increment_string(string) except IndexError: # Incrementing has gone out of the char array, move onto next length break yield string```

See also

References

  1. "Populations légales 2017". INSEE. Retrieved 6 January 2020.



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