2019 Open Harmonie mutuelle – Doubles

Sander Arends and Tristan-Samuel Weissborn were the defending champions[1] but lost in the semifinals to Jonathan Eysseric and Antonio Šančić.

Doubles
2019 Open Harmonie mutuelle
Champions	Jonathan Erlich Fabrice Martin
Runners-up	Jonathan Eysseric Antonio Šančić
Final score	7–6^(7–2), 7–6^(7–2)

Main article: 2019 Open Harmonie mutuelle

Jonathan Erlich and Fabrice Martin won the title after defeating Eysseric and Šančić 7–6^(7–2), 7–6^(7–2) in the final.

Seeds

1. Philipp Oswald / Leander Paes (First round)
2. Romain Arneodo / Hugo Nys (Quarterfinals)
3. Robert Galloway / Nathaniel Lammons (First round)
4. Jonathan Erlich / Fabrice Martin (Champions)

Draw

Key

• Q = Qualifier
• WC = Wild Card
• LL = Lucky Loser
• Alt = Alternate
• SE = Special Exempt
• PR = Protected Ranking
• ITF = ITF entry
• JE = Junior Exempt
• w/o = Walkover
• r = Retired
• d = Defaulted

First Round

Quarterfinals

Semifinals

Final

1

P Oswald L Paes

6

2

[8]

J Cerretani M-A Hüsler

4

6

[10]

J Cerretani M-A Hüsler

4

4

LD Martínez G Oliveira

6^2

4

ITF

A Artuñedo S Martos Gornés

6

6

ITF

A Artuñedo Sergio Martos Gornés

7^7

6

ITF

A Artuñedo S Martos Gornés

3

4

4

J Erlich F Martin

6

7^7

4

J Erlich F Martin

6

6

A Vasilevski A Vavassori

3

6^4

4

J Erlich F Martin

7^8

6^7

[10]

R Junaid D Pel

6

6

R Junaid D Pel

6^6

7^9

[6]

WC

E Furness M Guinard

4

2

4

J Erlich F Martin

7^7

7^7

WC

Q Halys G Jacq

6^3

6^2

J Eysseric A Šančić

6^2

6^2

S Arends T-S Weissborn

7^7

7^7

S Arends T-S Weissborn

6

7^7

ITF

D Added A Olivetti

6^4

6

[10]

ITF

D Added A Olivetti

4

6^5

3

R Galloway N Lammons

7^7

4

[8]

S Arends T-S Weissborn

3

5

J Eysseric A Šančić

6

6

J Eysseric A Šančić

6

7

S Stakhovsky S Walków

3

1

J Eysseric A Šančić

7^7

6

WC

Matteo Martineau C Moutet

4

4

2

R Arneodo H Nys

6^4

4

2

R Arneodo H Nys

6

6

References

1. "Tristan-Samuel Weissborn holt Doppeltitel in St. Brieuc". www.spox.com.

• Main Draw