2019 Kiskút Open – Singles

Nicoleta Dascălu won the title, defeating Irina Bara in an all-Romanian final, 7–5, 6–2.

Singles
2019 Kiskút Open
Champion Nicoleta Dascălu
Runner-up Irina Bara
Final score7–5, 6–2
Main article: 2019 Kiskút Open

This was the first edition of the tournament.[1]

Seeds
  1. Danka Kovinić (Quarterfinals)
  2. Irina-Camelia Begu (Semifinals)
  3. Katarina Zavatska (First round)
  4. Katarzyna Kawa (Quarterfinals)
  5. Viktoriya Tomova (Second round)
  6. Verónica Cepede Royg (Quarterfinals)
  7. Kristína Kučová (First round)
  8. Rebecca Šramková (Quarterfinals)

Draw

Key

Finals
Semifinals Final
          
  Irina Bara 6 6
  Çağla Büyükakçay 4 3
  Irina Bara 5 2
Q Nicoleta Dascălu 7 6
Q Nicoleta Dascălu 6 6
2 Irina-Camelia Begu 4 0

Top half
First Round Second Round Quarterfinals Semifinals
1 D Kovinić 6 6
  F Stollár 3 1 1 D Kovinić 6 6
WC A Nagy 4 4 Q N Potočnik 2 3
Q N Potočnik 6 6 1 D Kovinić 3 3
  I Bara 6 6 I Bara 6 6
  M Chwalińska 4 4 I Bara 7 2 6
Q IG Ghioroaie 65 4 5 V Tomova 5 6 3
5 V Tomova 77 6 I Bara 6 6
3 K Zavatska 2 2 Ç Büyükakçay 4 3
  Ç Büyükakçay 6 6 Ç Büyükakçay 5 6 7
Q M Zanevska 77 6 Q M Zanevska 7 2 5
Q L Bošković 61 3 Ç Büyükakçay 5 6 6
Q D Seguel 6 0 4 6 V Cepede Royg 7 1 3
WC D Drahota-Szabó 4 6 6 WC D Drahota-Szabó 6 3 2
  G Cé 1 0 6 V Cepede Royg 4 6 6
6 V Cepede Royg 6 6

Bottom half
First Round Second Round Quarterfinals Semifinals
7 K Kučová 1 2
Q N Dascălu 6 6 Q N Dascălu 78 77
  A Bondár 3 4 Q G García Pérez 66 62
Q G García Pérez 6 6 Q N Dascălu 6 6
Q S Waltert 6 6 4 K Kawa 3 3
  M Di Giuseppe 4 0 Q S Waltert 65 3
WC G Arn 77 2 1 4 K Kawa 77 6
4 K Kawa 65 6 6 Q N Dascălu 6 6
8 R Šramková 77 3 6 2 I-C Begu 4 0
  RL Jani 65 6 3 8 R Šramková 6 6
PR S Celik 2 1 WC D Gálfi 4 3
WC D Gálfi 6 6 8 R Šramková 1 3
  P Ormaechea 7 7 2 I-C Begu 6 6
  H Tan 5 5 P Ormaechea 2 4
  M Fręch 1 1 2 I-C Begu 6 6
2 I-C Begu 6 6
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References
  1. "W60 Székesfehérvár". www.itftennis.com.
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