2019 Amex-Istanbul Challenger – Singles

Corentin Moutet was the defending champion[1] but chose not to defend his title.

Singles
2019 Amex-Istanbul Challenger
Champion Ugo Humbert
Runner-up Denis Istomin
Final score6–2, 6–2

Ugo Humbert won the title after defeating Denis Istomin 6–2, 6–2 in the final.

Seeds

All seeds receive a bye into the second round.

  1. Ugo Humbert (Champion)
  2. Marcel Granollers (Withdrew)
  3. Marius Copil (Third round)
  4. Malek Jaziri (Withdrew)
  5. Denis Istomin (Final)
  6. Lukáš Rosol (Third round)
  7. Maxime Janvier (Second round)
  8. Ramkumar Ramanathan (Third round)
  9. Roberto Marcora (Third round)
  10. Ruben Bemelmans (Quarterfinals)
  11. Jay Clarke (Second round)
  12. Nicola Kuhn (Quarterfinals)
  13. Aleksandr Nedovyesov (Quarterfinals)
  14. Roman Safiullin (Second round)
  15. Santiago Giraldo (Withdrew)
  16. Blaž Kavčič (Semifinals)
  17. Matteo Viola (Third round)

Draw

Key

Finals

Quarterfinals Semifinals Final
               
1 Ugo Humbert 63 7 6
10 Ruben Bemelmans 77 5 2
1 Ugo Humbert 6 6
16 Blaž Kavčič 2 1
16 Blaž Kavčič 6 6
12 Nicola Kuhn 3 0
1 Ugo Humbert 6 6
5 Denis Istomin 2 2
Botic van de Zandschulp 6 6
David Poljak 3 2
Botic van de Zandschulp 3 6 3
5 Denis Istomin 6 3 6
5 Denis Istomin 6 6
13 Aleksandr Nedovyesov 3 4

Top half

Section 1

First Round Second Round Third Round Quarterfinals
1 U Humbert 6 6
Alt Marek Gengel 6 6 Alt M Gengel 1 2
S Danilov 2 0 1 U Humbert 6 6
Hugo Grenier 6 5 6 H Grenier 2 4
J Rodionov 3 7 2 H Grenier 6 6
Alt S Arends 2 3
1 U Humbert 63 7 6
10 R Bemelmans 77 5 2
10 R Bemelmans 6 7
Mircea-Alexandru Jecan 6 6 M-A Jecan 2 5
Shalva Dzhanashiya 2 0 10 R Bemelmans 6 6
Denis Yevseyev 64 2 6 L Rosol 4 3
G Blancaneaux 77 6 G Blancaneaux 2 6 4
6 L Rosol 6 3 6

Section 2

First Round Second Round Third Round Quarterfinals
3 M Copil 6 0 6
A Lazov 5 6 1 R Roumane 3 6 2
R Roumane 7 2 6 3 M Copil 3 5
Alt Burak Can Yılmaz 2 1 16 B Kavčič 6 7
FC Jianu 6 6 FC Jianu 710 3 1r
16 B Kavčič 68 6 2
16 B Kavčič 6 6
12 N Kuhn 3 0
12 N Kuhn 6 6
WC Kirill Saplin 0 1 Alt VV Cornea 2 4
Alt VV Cornea 6 6 12 N Kuhn 6 7
WC M İlhan 6 6 8 R Ramanathan 3 5
WC Mert Naci Türker 4 3 WC M İlhan 2 2
8 R Ramanathan 6 6

Bottom half

Section 3

First Round Second Round Third Round Quarterfinals
7 M Janvier 6 4 2
A Dubrivnyy 3 2 B van de Zandschulp 1 6 6
B van de Zandschulp 6 6 B van de Zandschulp 1 6 6
L Miedler 6 6 L Miedler 6 1 3
A Müller 4 4 L Miedler 6 7
11 J Clarke 3 5
B van de Zandschulp 6 6
D Poljak 3 2
14 R Safiullin 4 6 2
A Golubev 4 5 D Poljak 6 3 6
David Poljak 6 7 D Poljak 64 6 6
WC HVN Rune 1 3 17 M Viola 77 4 4
T Lamasine 6 6 T Lamasine 4 1
17 M Viola 6 6

Section 4

First Round Second Round Third Round Quarterfinals
5 D Istomin 69 6 2
M Neuchrist 2r M Zverev 711 2 1r
M Zverev 5 5 D Istomin 3 6 711
E Karlovskiy 3 65 9 R Marcora 6 3 69
A Šetkić 6 77 A Šetkić 1 1
9 R Marcora 6 6
5 D Istomin 6 6
13 A Nedovyesov 3 4
13 A Nedovyesov 6 6
WC Baran Cengiz 6 6 WC B Cengiz 1 4
S Carr 3 2 13 A Nedovyesov 6 3
Y Mertens 5 6 63 E Hoyt 2 0r
E Hoyt 7 4 77 E Hoyt 6 7
Alt M Elgin 4 5
gollark: I meant loading them was very parallelizable, not playing them. Not sure if Minecraft does that.
gollark: It's silly though, they're very parallelizable.
gollark: If you haven't found it yet you probably want to look up "ARM ABI conventions" or something.
gollark: It would probably be helpful if you explain why you need this to avoid XY problems.
gollark: The general standard for encrypted partition things, on Linux anyway, is LUKS. You *may* just be able to put a valid LUKS header in front of a block of random data, but it would be basically equivalent to just *actually* make an encrypted partition with a random key you then delete.

References

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