2018 Shanghai Challenger – Doubles

Toshihide Matsui and Yi Chu-huan were the defending champions but only Yi chose to defend his title, partnering Peng Hsien-yin. Yi lost in the first round to Gong Maoxin and Zhang Ze.

Doubles
2018 Shanghai Challenger
Champions Gong Maoxin
Zhang Ze
Runners-up Hua Runhao
Zhang Zhizhen
Final score6–4, 3–6, [10–4]

Gong and Zhang Ze went on to win the title after defeating Hua Runhao and Zhang Zhizhen 6–4, 3–6, [10–4] in the final.

Seeds

Draw

Key

First Round Quarterfinals Semifinals Final
1 C-p Hsieh
C Rungkat
6 6
WC Y He
Zeng Shi Hong
2 1 1 C-p Hsieh
C Rungkat
6 5 [10]
F Sun
D Wu
6 6 F Sun
D Wu
4 7 [1]
A Bublik
M Kecmanović
2 4 1 C-p Hsieh
C Rungkat
67 4
3 T Chen
M Purcell
4 2 WC R Hua
Zh Zhang
79 6
WC R Hua
Zh Zhang
6 6 WC R Hua
Zh Zhang
6 6
WC X Gao
R Te
65 4 Alt A Bega
T Lamasine
4 4
Alt A Bega
T Lamasine
77 6 WC R Hua
Zh Zhang
4 6 [4]
F Gaio
E López Pérez
2 M Gong
Ze Zhang
6 3 [10]
F Peliwo
B Schnur
w/o F Peliwo
B Schnur
3 4
B Mousley
A Santillan
4 62 4 VS Prashanth
V Vardhan
6 6
4 VS Prashanth
V Vardhan
6 77 4 VS Prashanth
V Vardhan
2 64
A Lawson
Z Li
4 6 [10] 2 M Gong
Ze Zhang
6 77
H Moriya
R Safiullin
6 0 [8] A Lawson
Z Li
4 77 [4]
H-y Peng
C-h Yi
4 68 2 M Gong
Ze Zhang
6 62 [10]
2 M Gong
Ze Zhang
6 710
gollark: It probably did just mean 3 moles of Fe2O3, not 3 times 2 times Fe2O3.
gollark: <@288035900980461579> Did the question just ask for 3 moles of Fe2O3, or 3 of "2Fe2O3" somehow?
gollark: Yes, so 3 of that would be 6 moles Fe2O3.
gollark: Did it *come* with the formula and say "how many moles of O2 do you need to get three 2Fe2O3s", or what?
gollark: ... wait, no, I'm being silly, you'd still have the same ratio of thing to other thing.

References

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