2016 Las Vegas Challenger – Singles

Thiemo de Bakker was the defending champion but chose not to defend his title.

Singles
2016 Las Vegas Challenger
Champion Sam Groth
Runner-up Santiago Giraldo
Final score6–7(4–7), 6–4, 7–5
Main article: 2016 Las Vegas Challenger

Sam Groth won the title after defeating Santiago Giraldo 6–7(4–7), 6–4, 7–5 in the final.

Seeds
  1. Víctor Estrella Burgos (First round)
  2. Frances Tiafoe (First round)
  3. Bjorn Fratangelo (Second round)
  4. Santiago Giraldo (Final)
  5. Darian King (Second round)
  6. Denis Kudla (First round)
  7. Dennis Novikov (Second round)
  8. Marco Trungelliti (Semifinals)

Draw

Key

Finals
Semifinals Final
          
8 Marco Trungelliti 5 77 65
4 Santiago Giraldo 7 62 77
4 Santiago Giraldo 77 4 5
Sam Groth 64 6 7
  Sam Groth 77 6
Sekou Bangoura 65 4

Top half
First Round Second Round Quarterfinals Semifinals
1 V Estrella Burgos 3 1
G Žemlja 6 6 G Žemlja 6 6
Q S Caruso 6 6 Q S Caruso 3 4
M Arévalo 2 4 G Žemlja 63 65
E Escobedo 6 6 8 M Trungelliti 77 77
WC A Falla 4 3 E Escobedo 5 0
G Clezar 6 4 4 8 M Trungelliti 7 6
8 M Trungelliti 3 6 6 8 M Trungelliti 5 77 65
4 S Giraldo 6 6 4 S Giraldo 7 62 77
Q R Ortega Olmedo 3 2 4 S Giraldo w/o
LL T Vorster 4 65 P Polansky
P Polansky 6 77 4 S Giraldo 64 6 6
T Paul 65 1r WC M Torpegaard 77 3 2
A Krajicek 77 2 A Krajicek 66 3
WC M Torpegaard 6 6 WC M Torpegaard 78 6
6 D Kudla 3 2

Bottom half
First Round Second Round Quarterfinals Semifinals
5 D King 65 7 0
E Struvay 77 5 0d 5 D King 4 4
WC Evan Song 4 4 T Sandgren 6 6
T Sandgren 6 6 T Sandgren 62 5
Q L Glasspool 5 3 S Groth 77 7
S Groth 7 6 S Groth 77 7
Q L Broady 6 3 3 3 B Fratangelo 63 5
3 B Fratangelo 1 6 6 S Groth 77 6
7 D Novikov 6 6 S Bangoura 65 4
J McGee 4 1 7 D Novikov 66 4
A Sarkissian 62 0r S Bangoura 78 6
S Bangoura 77 0 S Bangoura 6 3 6
Z Li 6 77 SE B Klein 4 6 4
WC Jakob Amilon 1 65 Z Li 1 6 3
SE B Klein 2 7 6 SE B Klein 6 1 6
2 F Tiafoe 6 5 3
gollark: It's very\* readable\*\*.
gollark: ```javascriptconst spaces = regex(/^ */)const whitespace = regex(/^[ \n\t]*/)const name = regex(/^[^ \n\t():]+/)const code = many(coroutine(function*() { yield spaces return yield choice([ coroutine(function*() { yield char("(") const x = yield code yield spaces yield char(")") return x }), name ])}))const program = sequenceOf([ many1(coroutine(function*() { yield whitespace const n = yield name yield whitespace yield str(":=") const c = yield code return { code: c, name: n } })), possibly(whitespace)]).map(([x, _]) => x)```parsing™
gollark: It was very elegant. I combinated™ it in a few lines of code.
gollark: It went nicely and I had a cool parser and all until it turned out that we were accidentally pushing to the wrong end of a list or something in a stupidly hard to debug way.
gollark: Fun times, that was. We were using JS to implement that weird stacky language.

References
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