2016 Challenger Banque Nationale de Granby – Men's Doubles
Philip Bester and Peter Polansky were the defending champions, but lost in the semifinals to Guilherme Clezar and Alejandro González.
Men's Doubles | |
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2016 Challenger Banque Nationale de Granby | |
Champion | ![]() ![]() |
Runner-up | ![]() ![]() |
Final score | 3–6, 6–1, [12–10] |
Clezar and González won the title, defeating Saketh Myneni and Sanam Singh 3–6, 6–1, [12–10] in the final.
Seeds
Sekou Bangoura / David O'Hare (First round) Jarryd Chaplin / Mitchell Krueger (Semifinals) Saketh Myneni / Sanam Singh (Final) Philip Bester / Peter Polansky (Semifinals)
Draw
Key
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- Alt = Alternate
- SE = Special Exempt
- PR = Protected Ranking
- ITF = ITF entry
- JE = Junior Exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
First Round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | ![]() ![]() | 77 | 4 | [10] | |||||||||||||||||||||||
WC | ![]() ![]() | 64 | 6 | [12] | WC | ![]() ![]() | 4 | 6 | [7] | ||||||||||||||||||
![]() ![]() | 77 | 6 | ![]() ![]() | 6 | 4 | [10] | |||||||||||||||||||||
WC | ![]() ![]() | 65 | 2 | ![]() ![]() | 6 | 6 | |||||||||||||||||||||
4 | ![]() ![]() | 7 | 6 | 4 | ![]() ![]() | 4 | 2 | ||||||||||||||||||||
![]() ![]() | 5 | 4 | 4 | ![]() ![]() | 6 | 6 | |||||||||||||||||||||
![]() ![]() | 7 | 7 | ![]() ![]() | 3 | 2 | ||||||||||||||||||||||
WC | ![]() ![]() | 5 | 5 | ![]() ![]() | 3 | 6 | [12] | ||||||||||||||||||||
![]() ![]() | 6 | 6 | 3 | ![]() ![]() | 6 | 1 | [10] | ||||||||||||||||||||
![]() ![]() | 4 | 4 | ![]() ![]() | 77 | 62 | [9] | |||||||||||||||||||||
![]() ![]() | 4 | 2 | 3 | ![]() ![]() | 65 | 77 | [11] | ||||||||||||||||||||
3 | ![]() ![]() | 6 | 6 | 3 | ![]() ![]() | 6 | 6 | ||||||||||||||||||||
![]() ![]() | 77 | 77 | 2 | ![]() ![]() | 3 | 3 | |||||||||||||||||||||
![]() ![]() | 65 | 62 | ![]() ![]() | 77 | 5 | [8] | |||||||||||||||||||||
Alt | ![]() ![]() | 77 | 4 | [4] | 2 | ![]() ![]() | 61 | 7 | [10] | ||||||||||||||||||
2 | ![]() ![]() | 65 | 6 | [10] |
gollark: `y_1` is the `y` of the first point, I'm sure you can infer the rest.
gollark: `m = y_1-y_2/x_1-x_2`, `c = y_1 - mx_1`, I think.
gollark: You can rearrange the equation for `c` and substitute in one of the points to get `c`.
gollark: Straight lines have the equation `y = mx + c`, where m and c are constants. `m` is the gradient, which is just the difference in y between those points divided by the difference in x.
gollark: "Straight line" in what form?
References
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