2014 Sacramento Challenger – Doubles
John-Patrick Smith and Matt Reid were the defending champions, however they chose not to participate with each other. Smith partners Adam Hubble, whilst Reid partners Jose Statham.
Doubles | |
---|---|
2014 Sacramento Challenger | |
Champions | |
Runners-up | |
Final score | 6–3, 6–2 |
Adam Hubble and John-Patrick Smith won the title by defeating Peter Polansky and Adil Shamasdin 6–3, 6–2 in the final.
Seeds
Marcus Daniell / Artem Sitak (Semifinals) Peter Polansky / Adil Shamasdin (Final) Bradley Klahn / Tim Smyczek (withdrew) Sekou Bangoura / Tennys Sandgren (First round)
Draw
Key
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- Alt = Alternate
- SE = Special Exempt
- PR = Protected Ranking
- ITF = ITF entry
- JE = Junior Exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | 6 | 77 | |||||||||||||||||||||||||
WC | 1 | 64 | 1 | 2 | 78 | [10] | |||||||||||||||||||||
Q | 3 | 3 | 6 | 66 | [4] | ||||||||||||||||||||||
6 | 6 | 1 | 4 | 77 | [14] | ||||||||||||||||||||||
PR/4 | 1 | 4 | PR | 6 | 65 | [16] | |||||||||||||||||||||
PR | 6 | 6 | PR | 6 | 66 | [10] | |||||||||||||||||||||
3 | 4 | 4 | 78 | [8] | |||||||||||||||||||||||
6 | 6 | PR | 6 | 6 | |||||||||||||||||||||||
5 | 6 | [10] | 2 | 3 | 2 | ||||||||||||||||||||||
WC | 7 | 4 | [2] | 6 | 4 | [7] | |||||||||||||||||||||
WC | 7 | 6 | WC | 4 | 6 | [10] | |||||||||||||||||||||
LL | 5 | 4 | WC | 4 | 2 | ||||||||||||||||||||||
6 | 4 | [8] | 2 | 6 | 6 | ||||||||||||||||||||||
PR | 3 | 6 | [10] | 2 | 4 | ||||||||||||||||||||||
66 | 0 | 2 | 6 | 6 | |||||||||||||||||||||||
2 | 77 | 6 |
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References
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