2008 Zurich Open – Doubles
Květa Peschke and Rennae Stubbs were the defending champions, but lost in the first round to Anna-Lena Grönefeld and Patty Schnyder.
Doubles | |
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2008 Zurich Open | |
Champions | ![]() ![]() |
Runners-up | ![]() ![]() |
Final score | 6–1, 7–6(3) |
Cara Black and Liezel Huber won in the final 6–1, 7–6(3), against Anna-Lena Grönefeld and Patty Schnyder.
Seeds
Cara Black / Liezel Huber (Champions) Katarina Srebotnik / Ai Sugiyama (Semifinals) Anabel Medina Garrigues / Virginia Ruano Pascual (First Round) Květa Peschke / Rennae Stubbs (First Round)
Draw
Key
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- Alt = Alternate
- SE = Special Exempt
- PR = Protected Ranking
- ITF = ITF entry
- JE = Junior Exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
Draw
First Round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | ![]() ![]() | 6 | 6 | ||||||||||||||||||||||||
WC | ![]() ![]() | 2 | 3 | 1 | ![]() ![]() | w/o | |||||||||||||||||||||
![]() ![]() | 4 | 0 | ![]() ![]() | ||||||||||||||||||||||||
![]() ![]() | 6 | 6 | 1 | ![]() ![]() | 6 | 4 | [10] | ||||||||||||||||||||
3 | ![]() ![]() | 2 | 4 | ![]() ![]() | 2 | 6 | [6] | ||||||||||||||||||||
![]() ![]() | 6 | 6 | ![]() ![]() | 6 | 2 | [6] | |||||||||||||||||||||
![]() ![]() | 4 | 2 | ![]() ![]() | 2 | 6 | [10] | |||||||||||||||||||||
![]() ![]() | 6 | 6 | 1 | ![]() ![]() | 6 | 7 | |||||||||||||||||||||
![]() ![]() | 3 | 61 | WC | ![]() ![]() | 1 | 63 | |||||||||||||||||||||
![]() ![]() | 6 | 7 | ![]() ![]() | 67 | 3 | ||||||||||||||||||||||
WC | ![]() ![]() | 3 | 6 | [12] | WC | ![]() ![]() | 7 | 6 | |||||||||||||||||||
4 | ![]() ![]() | 6 | 4 | [10] | WC | ![]() ![]() | 6 | 0 | [10] | ||||||||||||||||||
![]() ![]() | 1 | 2 | 2 | ![]() ![]() | 4 | 6 | [8] | ||||||||||||||||||||
![]() ![]() | 6 | 6 | ![]() ![]() | 6 | 3 | [6] | |||||||||||||||||||||
![]() ![]() | 1 | 4 | 2 | ![]() ![]() | 2 | 6 | [10] | ||||||||||||||||||||
2 | ![]() ![]() | 6 | 6 |
gollark: It just picks deterministically.
gollark: Or it might find * or - or something.
gollark: So, for example, if you call `Number(1, 3)`, it will find `(+) :: Number -> Number -> Number` and use that to return `4`.
gollark: The way *this* works is that when you call them, they scan all extant functions for things returning values implementing that trait which can be run with the provided arguments.
gollark: Good, good.
External links
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