2006 Rogers Cup – Doubles

Doubles
	2006 Rogers Cup
Champions	Martina Navratilova; Nadia Petrova
Runners-up	Cara Black; Anna-Lena Grönefeld
Final score	6–1, 6–2

Anna-Lena Grönefeld and Martina Navratilova were the defending champions. They were both present but did not compete together.
Grönefeld partnered with Cara Black, but Navratilova and partner Nadia Petrova defeated them 6–1, 6–2 in the final.

Seeds

The top four seeds received a bye into the second round.

Semifinals				Final


	Martina Navratilova Nadia Petrova	6	6

	Marion Bartoli Shahar Pe'er	3	3
					Martina Navratilova Nadia Petrova	6	6

				2	Cara Black Anna-Lena Grönefeld	1	2
4	Dinara Safina Katarina Srebotnik	2	2

2	Cara Black Anna-Lena Grönefeld	6	6

First Round					Second Round				Quarterfinals					Semifinals


					1	Z Yan J Zheng	w/o
LL	J Kostanić V Uhlířová	2	2			J Janković N Li
	J Janković N Li	6	6						1	Z Yan J Zheng	4	6	4
LL	S Fichman V Tétreault	0	1							M Navratilova N Petrova	6	3	6
	M Navratilova N Petrova	6	6			M Navratilova N Petrova	7	6
	A Jidkova MJ Martínez Sánchez	6	4	4	7	G Dulko C Morariu	6¹	2
7	G Dulko C Morariu	3	6	6											M Navratilova N Petrova	6	6
															M Bartoli S Pe'er	3	3
					3	K Peschke F Schiavone	7	6
	M Domachowska S Mirza	6	2	5		T Garbin M Tu	5	0
	T Garbin M Tu	3	6	7					3	K Peschke F Schiavone	2	6	0
	M Bartoli S Pe'er	6	6							M Bartoli S Pe'er	6	3	6
WC	S Dubois A Wozniak	3	1			M Bartoli S Pe'er	6	7
	A Bondarenko K Bondarenko	6	6			A Bondarenko K Bondarenko	3	5
5	V Ruano Pascual P Suárez	2	3

gollark: I know 0.2 physics or more or less.

gollark: School *is* a number of cryoapioforms, really.

gollark: Or somewhat self-regularizing discrete ones.

gollark: I mean, look at something something continuous chaotic systems.

gollark: Aren't discreteness and small changes causing big differences somewhat separate, though?

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