1991 Speedway World Pairs Championship
The 1991 Speedway World Pairs Championship was the twenty-second FIM Speedway World Pairs Championship. The final took place in Poznań, Poland. The championship was won by Denmark (28 points) who beat Sweden (24 points) and Norway (19 points).[1]
1991 World Pairs Championship | |||
Previous: | 1990 | Next: | 1992 |
World final
Poznań, Olimpia Poznań Stadium
Pos. | Team | Rider | Points |
---|---|---|---|
![]() | ![]() | Hans Nielsen | 14 |
Jan O. Pedersen | 14 | ||
Tommy Knudsen | — | ||
![]() | ![]() | Henrik Gustafsson | 9 |
Jimmy Nilsen | 8 | ||
Per Jonsson | 7 | ||
![]() | ![]() | Lars Gunnestad | 11 |
Einar Kyllingstad | 8 | ||
Tor Einar Hielm | — | ||
4 | ![]() | Gerd Riss | 9 |
Klaus Lausch | 9 | ||
Tommy Dunker | — | ||
5 | ![]() | Bohumil Brhel | 12 |
Roman Matousek | 6 | ||
Zdenek Tesar | 0 | ||
6 | ![]() | Armando Castagna | 9 |
Valentino Furlanetto | 1 | ||
Fabrizio Vesprini | 0 | ||
7 | ![]() | Ryszard Dołomisiewicz | 5 |
Piotr Świst | 3 | ||
Wojciech Załuski | 1 |
gollark: It would be quite annoying on larger things, but if you had, say, a 3-sided die, a 4-sided one, and a 5-sided one, and wanted to have 2 of them show a 1, then the possibilities are just 1, 1, anything and anything, 1, 1 (order is 3-sided, 4-sided, 5-sided).So you can work out the probability of each case (1/3 * 1*4 * 1 and 1 * 1/4 * 1/5) and add them.
gollark: Enumerate all the different possibilities where you have X dice showing 3, work out the probability of each, then add them?
gollark: Just multiply the probabilities for getting side X on each die together?
gollark: You also are probably not running Haskell with its giant runtime on a microcontroller doing those things.
gollark: My friend likes Haskell but also spends time reading incomprehensible papers on logic and type theory and such.
See also
References
- "Zapomniane turnieje: Mistrzostwa Świata Par (część 4)" (in Polish). SportoweFakty.pl. 2009-08-19. Archived from the original on 2009-09-04. Retrieved 2009-08-23.
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