1988 Ronde van Nederland
These are the results for the 28th edition of the Ronde van Nederland cycling race, which was held from August 15 to August 20, 1988. The race started in Groningen (Groningen) and finished after 859 kilometres in Gulpen (Limburg).
Stages
| Date | Stage | Length | Notes |
|---|---|---|---|
| August 15 | Groningen-Groningen | 4.6 km | Prologue |
| August 16 | Groningen-Almelo | 206 km | |
| August 17 | Almelo-Huizen | 193 km | |
| August 18 | Huizen-Nieuwegein | 146 km | |
| August 19 | Nieuwegein-Beek/Ubbergen | 109 km | |
| 19 August | Groesbeek-Beek/Ubbergen | 16.7 km | Time trial |
| 20 August | Sittard-Gulpen | 191 km |
Final classification
| Position | Name | Team | Time |
|---|---|---|---|
| 1 |  |
20:58:48 | |
| 2 |  |
+ 0.16 | |
| 3 | |
+ 0.26 | |
| 4 | |
+ 0.52 | |
| 5 | |
+ 0.56 | |
| 6 | |
+ 0.57 | |
| 7 | .svg.png){kind=small} |
+ 1.26 | |
| 8 | |
+ 2.52 | |
| 9 | |
+ 2.59 | |
| 10 | |
+ 3.10 |
gollark: "is that whatever times whatever times whatever is constant"?
gollark: Pretty sure anything below 2.125, which 2.1249 is, should round to 2.12.
gollark: If you don't want the images and stuff it's only 15-ish gigabytes.
gollark: If you're tired of sometimes not being able to access Wikipedia, just download it!
gollark: The equation is 4FeS2 + 11O2 --> 2Fe2O3 + 8SO2. You want to know how many moles O2 are needed per mole FeS2, so that's 11/4 = 2.75. Then, since the question asks for how many moles O2 are needed with *3* moles FeS2, multiply by 3, and you get 8.25.
External links
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