1967 CONCACAF Championship qualification

For the 1967 CONCACAF Championship, a total of 10 teams entered the competition.  Honduras, as the hosts, and  Mexico, as the defending champions, qualified automatically, leaving 4 spots open for competition. The 8 teams were divided into 2 groups in which the top 2 in each group advanced to the final tournament.

Group 1

Played in Kingston, Jamaica.

The group was also referred to as the Red Stripe Trophy within Jamaica. The group was sponsored by Desnoes & Geddes, the brewery of Red Stripe beer.[1]

Pos	Team	Pld	W	D	L	GF	GA	GD	Pts
1	Haiti	4	3	1	0	7	3	+4	7
2	Trinidad and Tobago	4	2	1	1	7	7	0	5
3	Jamaica	4	1	2	1	4	4	0	4
4	Cuba	4	0	2	2	5	7	−2	2
5	Netherlands Antilles	4	0	2	2	4	6	−2	2

Source:

11 January 1967

Jamaica	1–1	Netherlands Antilles

Jamaica

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12 January 1967

Cuba	1–1	Haiti

Jamaica

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13 January 1967

Trinidad and Tobago	2–1	Netherlands Antilles
Small Archibald		Perez  (pen)

Jamaica

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14 January 1967

Jamaica	2–1	Cuba

Jamaica

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16 January 1967

Haiti	4–2	Trinidad and Tobago

Jamaica

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17 January 1967

Netherlands Antilles	2–2	Cuba
Dirks Perez		Hernandez Mico

Jamaica

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18 January 1967

Jamaica	1–1	Trinidad and Tobago

Jamaica

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19 January 1967

Haiti	1–0	Netherlands Antilles

Jamaica

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20 January 1967

Trinidad and Tobago	2–1	Cuba

Jamaica

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21 January 1967

Jamaica	0–1	Haiti

Jamaica

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Haiti and Trinidad and Tobago qualified for the final tournament.

Group 2

Played in Ciudad de Guatemala, Guatemala.

Pos	Team	Pld	W	D	L	GF	GA	GD	Pts
1	Guatemala	2	2	0	0	6	2	+4	4
2	Nicaragua	2	1	0	1	4	4	0	2
3	Panama	2	0	0	2	2	6	−4	0

Source:

13 February 1967

Guatemala	3–1	Panama

Guatemala

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15 February 1967

Guatemala	3–1	Nicaragua

Guatemala

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17 February 1967

Panama	1–3	Nicaragua

Guatemala

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Guatemala and Nicaragua qualified for the final tournament.

References

1. "Haitian goalkeeper suspended". Kingston Gleaner. 23 January 1967. p. 28.

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