1888 United States presidential election in Oregon
The 1888 United States presidential election in Oregon took place on November 6, 1888, as part of the 1888 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.
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Elections in Oregon | ||||||||||
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Oregon voted for the Republican nominee, Benjamin Harrison, over the Democratic nominee, incumbent President Grover Cleveland. Harrison won the state by a margin of 10.94%.
Results
1888 United States presidential election in Oregon[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Republican | Benjamin Harrison of Indiana | Levi Parsons Morton of New York | 33,291 | 53.82% | 3 | 100.00% | ||
Democratic | Grover Cleveland of New York | Allen Granberry Thurman of Ohio | 26,522 | 42.88% | 0 | 0.00% | ||
Prohibition | Clinton Bowen Fisk of New Jersey | John Anderson Brooks of Missouri | 1,677 | 2.71% | 0 | 0.00% | ||
United Labor Party | Robert Cowdrey | William Wakefield | 363 | 0.59% | 0 | 0.00% | ||
Total | 61,853 | 100.00% | 3 | 100.00% |
Notes
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References
- "1888 Presidential General Election Results - Oregon". U.S. Election Atlas. Retrieved 23 December 2013.
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