1888 United States presidential election in Oregon

The 1888 United States presidential election in Oregon took place on November 6, 1888, as part of the 1888 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

Main article: 1888 United States presidential election
1888 United States presidential election in Oregon
November 6, 1888
 
Nominee Benjamin Harrison Grover Cleveland
Party Republican Democratic
Home state Indiana New York
Running mate Levi P. Morton Allen G. Thurman
Electoral vote 3 0
Popular vote 33,291 26,522
Percentage 53.82% 42.88%
President before election

Grover Cleveland
Democratic

 Elected President

Benjamin Harrison
Republican

Elections in Oregon

Oregon voted for the Republican nominee, Benjamin Harrison, over the Democratic nominee, incumbent President Grover Cleveland. Harrison won the state by a margin of 10.94%.

Results
1888 United States presidential election in Oregon[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Benjamin Harrison of Indiana Levi Parsons Morton of New York 33,291 53.82% 3 100.00%
Democratic Grover Cleveland of New York Allen Granberry Thurman of Ohio 26,522 42.88% 0 0.00%
Prohibition Clinton Bowen Fisk of New Jersey John Anderson Brooks of Missouri 1,677 2.71% 0 0.00%
United Labor Party Robert Cowdrey William Wakefield 363 0.59% 0 0.00%
Total 61,853 100.00% 3 100.00%

Notes
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    References
    1. "1888 Presidential General Election Results - Oregon". U.S. Election Atlas. Retrieved 23 December 2013.


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