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I am on Intelx86 platform. I have make my entire disk a Solaris partition.
Below are the slice information in that Solaris partition
partition> p
Current partition table (original):
Total disk cylinders available: 6524 + 2 (reserved cylinders)
Part Tag Flag Cylinders Size Blocks
0 root wm 68 - 1141 8.23GB (1074/0/0) 17253810
1 swap wu 1 - 67 525.56MB (67/0/0) 1076355
2 backup wm 0 - 6523 49.98GB (6524/0/0) 104808060
3 unassigned wm 0 0 (0/0/0) 0
4 unassigned wm 0 0 (0/0/0) 0
5 unassigned wm 0 0 (0/0/0) 0
6 unassigned wm 0 0 (0/0/0) 0
7 home wm 1142 - 6522 41.22GB (5381/0/0) 86445765
8 boot wu 0 - 0 7.84MB (1/0/0) 16065
9 unassigned wm 0 0 (0/0/0) 0
My question would be
When you make a whole partition out of the disk, does the 1st sector in the partition = 1st sector in the disk?
Does the 1st sector (under the boot slice number 8) listed in the partition table above = 1st sector in the disk?
Solaris on x86 conforms to PC disk conventions, and therefore uses the MS-DOS partition table in the MBR. FWIW I was a developer on the team that first ported SunOS 20 years ago to x86. – sawdust – 2015-10-19T00:43:42.490
@sawdust good to hear that! so i would believe that the MBR = 1st sector of disk, and the solaris VTOC is in the fdisk primary partition - yea ? – Noob – 2015-10-19T11:26:40.873
@sawdust - are you also able to advise why oracle doc is installing the bootblock on s0 instead of s8/s2 for x86 partition ? (http://docs.oracle.com/cd/E19253-01/817-5093/disksxadd-45774/index.html)
– Noob – 2015-10-19T11:28:40.443"...solaris VTOC is in the fdisk primary partition - yea ?" -- Yes. I don't recall those other details. After the first x86 releases (Solaris 2.3 and 2.4), most disk utilities were reassigned to another group at another site (Boulder CO). I don't recall a disk layout like you show, IIRC for the initial versions, we used logical partitions for slices. They have had a lot of time to change this. – sawdust – 2015-10-21T00:18:50.650