Using grep, sed or awk to find words in between? I want to be able to extract the package name until .el7

Question

I am writing a script (bash/command-line) and I want to be able to extract the package name until .el7

x=dbus-sharp (an example package name - which changes)

example text file:

Building dbus-sharp-0.7.0-11.fc22 for epel7
Created task: 7970206
...
0 free  1 open  1 done  0 failed
  7970225 buildArch (dbus-sharp-0.7.0-11.el7.src.rpm, ppc64): free
  7970223 buildArch (dbus-sharp-0.7.0-11.el7.src.rpm, x86_64): open (buildhw-03.phx2.fedoraproject.org)
...

basically now I want

y=dbus-sharp-0.7.0-11.el7

It doesn't matter if I need to use grep, sed or awk.

I haven't had any luck googling for a similar solution.

Examples I have tried:

[me@h dbus-sharp]$ echo "Here is a String" | grep -Po '(?<=(Here )).*(?= String)'
is a

[me@h dbus-sharp]$ cat scratchdbus-sharp | grep -Po '(?<=(dbus)).*(?= el7)'
(no output?)

[me@h dbus-sharp]$ cat scratchdbus-sharp | awk '/dbus/,/el7/'
(it dumps the whole text file?)

[me@h dbus-sharp]$ sed -n "/dbus/,/el7/p" scratchdbus-sharp
(again the whole text file is dumped)

[me@h dbus-sharp]$ grep -m 1 "dbus-sharp" scratchdbus-sharp 
Building dbus-sharp-0.7.0-11.fc22 for epel7

Guess I should also note that epel7 will be in the text file(s) which will also cause a match for 'el7' complicating things.

Answer 1

A grep solution:

grep -m 1 -oP 'dbus[^ ]+\.el7' file

-m 1 prints only one match, -o only the matching part and -P uses Perl regex.

And a sed solution:

sed -n 's/.*\(dbus.*\.el7\).*/\1/p' file | head -1

Removes all before and after dbus.*el7 and prints it (p), but only the first match (head -1).