Evaluating false in bash with multiple commands without a subshell

Question

Bash evaluates the logical operators such that && always takes precedence. So for example:

false || echo 1 && echo 2
1
2

and

true || echo 1 && echo 2
2

Ok. So lets say I want the output to be like this:

false || (echo 1 && echo 2)

But without invoking a subshell.

The only solution I could think of is this:

false || if true; then echo 1; echo 2; fi
1
2

Is there any cleaner way, similar to parenthesis in C, to group commands together without having to invoke a subshell?

Answer 1

false || { echo 1 && echo 2; }