1998 Boston Cup – Doubles

Lisa Raymond and Rennae Stubbs won in the final 64, 64 against Mariaan de Swardt and Mary Joe Fernández.

Doubles
1998 Boston Cup
Champions Lisa Raymond
Rennae Stubbs
Runners-up Mariaan de Swardt
Mary Joe Fernández
Final score64, 64

Seeds

Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated.

  1. Lisa Raymond / Rennae Stubbs (Champions)
  2. Naoko Kijimuta / Nana Miyagi (First Round)
  3. Kristine Kunce / Corina Morariu (First Round)
  4. Amanda Coetzer / Barbara Schett (First Round)

Draw

Key

First Round Quarterfinals Semifinals Final
1 L Raymond
R Stubbs
6 6  
  E deLone
S-T Wang
3 1   1 L Raymond
R Stubbs
6 6  
  N de Villiers
L McShea
6 1 4   S Farina
A Huber
4 3  
  S Farina
A Huber
1 6 6 1 L Raymond
R Stubbs
7 6  
3 K Kunce
C Morariu
2 2   Q C Black
I Selyutina
6 1  
Q C Black
I Selyutina
6 6   Q C Black
I Selyutina
6 4 6
  A Ellwood
T Musgrave
w/o       A Ellwood
T Musgrave
2 6 2
  O Barabanschikova
E Likhovtseva
      1 Lisa Raymond
Rennae Stubbs
6 6  
  L Horn
M Paz
4 3     Mariaan de Swardt
Mary Joe Fernández
4 4  
  R McQuillan
N Pratt
6 6     R McQuillan
N Pratt
3 3  
  C Cristea
R Dragomir
1 7 6   C Cristea
R Dragomir
6 6  
4 A Coetzer
B Schett
6 6 2   C Cristea
R Dragomir
3 7 4
  K Freye
Y Yoshida
6 6     M de Swardt
M J Fernández
6 5 6
WC S Kleinová
B Rippner
2 1     K Freye
Y Yoshida
3 3  
  M de Swardt
M J Fernández
6 7     M de Swardt
M J Fernández
6 6  
2 N Kijimuta
N Miyagi
1 6  
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.