1996 United States presidential election in the District of Columbia

The 1996 United States presidential election in the District of Columbia took place on November 5, 1996, as part of the 1996 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

1996 United States presidential election in the District of Columbia

November 5, 1996
 
Nominee Bill Clinton Bob Dole
Party Democratic Republican
Home state Arkansas Kansas
Running mate Al Gore Jack Kemp
Electoral vote 3 0
Popular vote 158,220 17,339
Percentage 85.19% 9.34%

District Result
Clinton
  80-90%


President before election

Bill Clinton
Democratic

Elected President

Bill Clinton
Democratic

Washington, D.C. was won by President Bill Clinton (D) over Senator Bob Dole (R-KS), with Clinton winning 85.19% to 9.34% by a margin of 75.85%. Political activist Ralph Nader (Green Party) finished in third, with 2.57% of the popular vote, and businessman Ross Perot (Reform Party) finished in fourth, with 1.94%.[1]

Washington, D.C. was again Ross Perot's worst performance in the country. This is also the only time Perot finished fourth in any location in either 1992 or 1996.

Results

1996 United States presidential election in Washington, D. C.
Party Candidate Running mate Votes Percentage Electoral votes
Democratic Bill Clinton (incumbent) Al Gore 158,220 85.19% 3
Republican Bob Dole Jack Kemp 17,339 9.34% 0
Green Ralph Nader Winona LaDuke 4,780 2.57% 0
Reform Ross Perot Patrick Choate 3,611 1.94% 0
No party Write-in 648 0.35% 0
Libertarian Harry Browne Jo Jorgensen 588 0.32% 0
Natural Law Dr. John Hagelin Dr. V. Tompkins 283 0.15% 0
Socialist Workers Party James Harris Laura Garza 257 0.14% 0

See also

References

This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.