Seward Township, Kosciusko County, Indiana

Seward Township is one of seventeen townships in Kosciusko County, Indiana. As of the 2010 census, its population was 2,567 and it contained 1,385 housing units.[3]

Seward Township
Coordinates: 41°06′29″N 85°56′46″W
CountryUnited States
StateIndiana
CountyKosciusko
Government
  TypeIndiana township
Area
  Total36.27 sq mi (93.9 km2)
  Land34.98 sq mi (90.6 km2)
  Water1.3 sq mi (3 km2)
Elevation876 ft (267 m)
Population
 (2010)
  Total2,567
  Density73.4/sq mi (28.3/km2)
Time zoneUTC-5 (Eastern (EST))
  Summer (DST)UTC-4 (EDT)
FIPS code18-68796[2]
GNIS feature ID453840

Seward Township was organized in 1859.[4]

Geography

According to the 2010 census, the township has a total area of 36.27 square miles (93.9 km2), of which 34.98 square miles (90.6 km2) (or 96.44%) is land and 1.3 square miles (3.4 km2) (or 3.58%) is water.[3]

Cities and towns

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References



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