Sękowice, Lubusz Voivodeship
Sękowice [sɛnkɔˈvit͡sɛ] (German: Schenkendorf) is a village in the administrative district of Gmina Gubin, within Krosno Odrzańskie County, Lubusz Voivodeship, in western Poland, close to the German border.[1] It lies approximately 4 kilometres (2 mi) south of Gubin, 30 km (19 mi) south-west of Krosno Odrzańskie, and 55 km (34 mi) west of Zielona Góra.
Sękowice | |
|---|---|
Village | |
  Sękowice | |
| Coordinates: 51°55′N 14°43′E | |
| Country |  |
| Voivodeship | Lubusz |
| County | Krosno Odrzańskie |
| Gmina | Gmina Gubin |
Before 1945 the area was part of Germany (see Territorial changes of Poland after World War II).
References
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